Question

Which function has a range of (-pi/2,pi/2)

Answer 1

ANSWER

$y = \tan^{ - 1} (x)$

EXPLANATION

The inverse tangent function has two horizontal asymptotes

$y=\pm \frac{\pi}{2}$


Therefore it has a range of

$( - \frac{\pi}{2},\frac{\pi}{2} )$

The second choice is the correct option.