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3 years ago

A Canadian driving from Quebec to Montreal finds he has traveled 271 km. How many miles is this? There are 1.61 km in 1 mi

Physics

1 answer:

kotegsom [21]3 years ago

3 0

Answer:

168.32 mile

Explanation:

1 mile = 1.61 km

1.61 km = 1 mile

1 km = 1 / 1.61 mile

So, 271 km = 271 / 1.61 = 168.32 mile

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In Florida, once you have had your learner's license for _________________ without any traffic convictions, you will receive an

bogdanovich [222]

Answer:

One year

Explanation:

In Florida, once you have had your learner's license for 1 year without any traffic convictions, you will receive an intermediate license.

The rule for Florida is that if a driver drives safely without any conviction during that year of his trial, he will receive an intermediate license. This means that he is now completely eligible and safe to drive around Florida's roads.

I hope the answer is helpful.

Thanks for asking.

3 0

3 years ago

A child has an ear canal that is 1.3 cm long. Assume the speed of sound is v = 344 m/s.

kap26 [50]

Answer:

The frequencies are $(f, f_1) = (6615.4 \ Hz , 19846.2\ Hz)$

Explanation:

From the question we are told that

The length of the ear canal is $l = 1.3 \ cm =\frac{1.3}{100} = 0.013 \ m$

The speed of sound is assumed to be $v_s = 344 \ m/s$

Now taking look at a typical ear canal we see that we assume it is a closed pipe

Now the fundamental harmonics for the pipe(ear canal) is mathematically represented as

$f = \frac{v_s}{4 * l }$

substituting values

$f = \frac{344}{4 * 0.013 }$

$f = 6615.4 \ Hz$

Also the the second harmonic for the pipe (ear canal) is mathematically represented as

$f_1 = \frac{3v_s}{4 * l}$

substituting values

$f_1 = \frac{3 * 344}{4 * 0.013}$

$f_1 = 19846.2 \ Hz$

Given that sound would be loudest in the pipe at the frequency, it implies that the child will have an increased audible sensitivity at this frequencies

6 0

3 years ago

According to Newton's second law of motion, force can be calculated by multiplying an object's mass by its acceleration. If weig

madreJ [45]

You would do m*a so 65kg * 9.8 m/s^2 which equates to 637 Newton’s

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3 years ago

In which of these three situations is the object accelerating?

Marrrta [24]

The answer is A because it’s the only object moving forward.

6 0

3 years ago