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lesya [120]
3 years ago
9

Canada geese migrate essentially along a north–south direction for well over a thousand kilo-meters in some cases, traveling at

speeds up to about 100 km/h. If one goose is flying at 100 km/h relative to the air but a 40-km/h wind is blowing from west to east, (a) at what angle relative to the north–south direction should this bird head to travel directly southward relative to the ground? (b) How long will it take the goose to cover a ground distance of 500 km from north to south? (Note: Even on cloudy nights, many birds can navigate by using the earth’s magnetic field to fix the north–south direction.)
Physics
1 answer:
kotykmax [81]3 years ago
7 0

Answer:

a) 66.4 relative to the west in the south-west direction

b) 5.455 hours

Explanation:

a)If the wind is blowing east-ward at a speed of 40km/h, then the west component of the geese velocity must be 40km/h in order to counter balance it. Geese should be flying south-west at an angle of

cos(\alpha) = 40 / 100 = 0.4

\alpha = cos^{-1}(0.4) = 1.16 rad = 180\frac{1.16}{\pi} = 66.4^0 relative to the West

b) The south-component of the geese velocity is

100sin(\alpha) = 100sin(66.4^0) = 91.65 km/h

The time it would take for the geese to cover 500km at this rate is

t = 500 / 91.65 = 5.455 hours

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vovangra [49]

Acceleration can be defined as the rate of change in the velocity of an object. Option C is correct.

<h3>What is Acceleration?</h3>
  • It is defined as the rate of change in velocity.
  • It can also be defined as the rate of change in position in a particular direction.

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\Delta v - change in velocity

t - time

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Learn more about Velocity:

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2 years ago
The teacher shared a demonstration with the same students. She begin by standing on a desk, holding a book and an open piece of
bazaltina [42]

Answer:

I think its c

Explanation:

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Which changes will increase the rate of reaction during combustion? decreasing the area of contact between the reactants adding
STALIN [3.7K]
The correct answer is B. The addition of oxygen will increase the rate of combustion. oxygen and raw material (fuel) are the substrates for the combustion process, therefore, increase in the same will obviously increase combustion rate. Carbon in the fuel is converted into carbon dioxide and heat. 
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Read 2 more answers
When a slice of buttered toast is accidentally pushed over the edge of a counter, it rotates as it falls. If the distance to the
Masja [62]

Answer:

The smallest angular velocity is 4.42 rad/s and the largest angular velocity is 13.15 rad/s for the toast to hit and then topple to be butter-side down

Explanation:

62 cm = 0.62 m

Knowing that the vertical distance traveled is s = 0.62 m and gravitational acceleration is g = 9.81 m/s2, we can calculate the time of falling

s = gt^2/2

0.62 = 9.81t^2/2

t^2 = 2*0.62/9.81 = 0.13

t = \sqrt{0.13} = 0.36 s

If there's only 0.36s to rotate, and for the toast to hit and then topple to be butter-side down, then the angle of rotation must be between 90 and 270 degrees (Suppose that it starts with butter up and it rotates less than 1 revolution, or 360 degrees):

In other words (and units):

\frac{\pi}{2} \leq \theta \leq \frac{3\pi}{2} rad

As \omega = \theta / t:

\frac{\pi}{2} / t \leq \theta / t \leq \frac{3\pi}{2} / t rad/s

\frac{\pi}{2*0.36} \leq \omega \leq \frac{3\pi}{2*0.36} rad/s

4.42 \leq \omega \leq 13.25 rad/s

So the smallest angular velocity is 4.42 rad/s and the largest angular velocity is 13.15 rad/s for the toast to hit and then topple to be butter-side down

4 0
3 years ago
A truck is traveling down a road with a 4-percent grade at a speed of 75 mi/h when its brakes are applied to slow it down to 22.
kvasek [131]

Answer:

3.964 s

Explanation:

Metric unit conversion:

1 miles = 1.6 km = 1600 m.

1 hour = 60 minutes = 3600 seconds

75 mph = 75 * 1600 / 3600 = 33.3 m/s

22.5 mph = 22.5 * 1600/3600 = 10 m/s

Let g = 9.81 m/s2

Friction is the product of coefficient and normal force, which equals to the gravity

F_f = \mu N = \mu mg

The deceleration caused by friction is friction divided by mass according to Newton 2nd law.

a = F_f / m = \mu mg / m = \mu g = 0.6 *9.81 = 5.886 m/s^2

So the time required to decelerate from 33.3 m/s to 10 m/s so the wheels don't slide, with the rate of 5.886 m/s2 is

t = \frac{\Delta v}{a} = \frac{33.3 - 10}{5.886} = 3.964 s

3 0
3 years ago
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