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Y_Kistochka [10]

2 years ago

6

A 64kg wheel with radius 2.4m is rotating at 280rev/min. if you want to stop it in 30sec. (use point mass of moment of inertia)

A. how much work must be done to stop it? B. what is the required power?

1 answer:

AfilCa [17]2 years ago

4 0

Answer:

Alot of work must be done

Im not sure what the required power will be

Explanation:

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Which vector is the sum of vectors a and b

jeka57 [31]

Answer:

C

Explanation:

Vector A points up

Vector B points right

The combination must be both up and right which is C

5 0

3 years ago

Starting from rest, a 2.1x10^-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exert

Rainbow [258]

Answer:

a) The flea's speed when it leaves the ground is $v=1.88m/s$

b) The flea move $18cm$ upward while it is pushing off

Explanation:

Hi

<u>Knwons</u>

Mass $m=2.1\times 10^{-4} kg$ , Work $W=3.7\times 10^{-4} J$ and Force $F=0.41N$

a) Here we are going to use $W=\frac{1}{2} mv^{2}$ , so $v=\sqrt{\frac{2W}{m} }= \sqrt{\frac{2(3.7\times 10^{-4} J)}{2.1\times 10^{-4} kg} }=1.88m/s$

a) Here we are going to use $W=mgh$ , so $h=\frac{W}{mg}= \frac{3.7\times 10^{-4} J}{(2.1\times 10^{-4} kg)(9.8m/s^{2})} =0,1797m$ or $18cm$ approx.

7 0

3 years ago

Plzzzz help me with this!!!!?????

zepelin [54]

Neap tide is when sun and moon are aligned at 90 degrees
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3 years ago

Read 2 more answers

3.7. A dog searching for a bone walks 3.50 m south, then 8.20 m at an angle 23.1 degrees north of east, and finally 15.0 m west.

andriy [413]

Answer:

Explanation:

We shall represent displacement of dog in vector form , in terms of i , j , i representing east and j representing north .

Dog travels 3.5 m south .

Displacement D₁ = - 3.5 j

then dog travels 8.2 m , 23.1 degree north of east

Displacement D₂ = 8.2 cos23.1 i + 8.2 sin23 j

D₂ = 8.2 cos23.1 i + 8.2 sin23.1 j

= 7.54 i + 3.22 j

Third displacement

D₃ = - 15i

Total displacement = D₁ + D₂ + D₃

= - 3.5 j + 7.54 i + 3.22 j -15i

= - 7.46 i - 0.28 j

Magnitude of displacement = √ ( 7.46² + .28²)

= √(55.65 + .08 )

= 7.46 m

b ) Direction of displacement

If Ф be angle , displacement makes with west direction

TanФ = .08 / 55.65 = .00143

Ф = .082 degree south of west or almost west .

From east , this angle = 180 + .082 = 180.082 , counterclockwise .

5 0

2 years ago

A large meteoroid enters the Earth's atmosphere at a speed of 20.0 km/s and is not significantly slowed before entering the ocea

Shalnov [3]

The shock wave from the meteoroid in the lower atmosphere has a Mach angle of 0.948°.

(a) The meteoroid's speed $v_s=20 \mathrm{~km} / \mathrm{s}$

$=20 \times 10^3 \mathrm{~m} / \mathrm{s}$

Air sound wave speed $&v=331 \mathrm{~m} / \mathrm{s} \\$

Speed of the shock wave in Mach $&\qquad \theta=\sin ^{-1}\left(\frac{v}{v_s}\right)$

$\begin{aligned}&=\sin ^{-1}\left(\frac{331 \mathrm{~m} / \mathrm{s}}{20 \times 10^3 \mathrm{~m} / \mathrm{s}}\right) \\&=0.948^{\circ}\end{aligned}$

Hence, 0.948° is the Mach angle of the shock wave from the meteoroid in the lower atmosphere.

<h3>What is the speed of the meteoroid?</h3>

A meteoroid's speed can be loosely broken down into three categories: slow, medium, and fast.

Slow meteors move around the sun at a leisurely pace of about 32 kilometers per second (20 miles per second).
Medium-speed meteors travel around the sun at approximately 50 kilometers per second (30 miles per second),
while fast meteors zoom past at over 120 kilometers per second (75 miles per second)!

To learn more about meteoroid, visit:

brainly.com/question/1939309

#SPJ4

5 0

1 year ago