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Y_Kistochka [10]

2 years ago

6

A 64kg wheel with radius 2.4m is rotating at 280rev/min. if you want to stop it in 30sec. (use point mass of moment of inertia)

A. how much work must be done to stop it? B. what is the required power?

1 answer:

AfilCa [17]2 years ago

4 0

Answer:

Alot of work must be done

Im not sure what the required power will be

Explanation:

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TiliK225 [7]

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2 years ago

Describe at least four of the requirements (facts) that any model of solar system formation must include (according to the nebul

kvasek [131]

The nebular theory describes the formation of the solar system and states that the system began as a gigantic cloud of gas and dust called a nebula which eventually condensed to form the sun, planets and other objects in the solar system. The first fact speaks to the formation of the planets, where gravity pulled larger clumps of material closer to form solid rocky planets closer to the sun and gas giants further out. The second requirement is that a nearby explosion or super nova would have to disturb our nebula to trigger rotation and the eventual formation of the sun. The third requirement/fact is that the planets go around the sun in the same direction. the last fact is that the planets go around the sun within 6 degrees of a common plane. This indicates that the solar system formed from a spinning disk of materials.

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3 years ago

Which statement expresses the relationship between the frequency of emitted electrons and the energy they give off?

Nadusha1986 [10]

I think it would be the first choice

5 0

3 years ago

Read 2 more answers

You have a stopped pipe of adjustable length close to a taut 62.0-cm, 7.25-g wire under a tension of 3910 N . You want to adjust

Ber [7]

Answer:

L = 6 cm

Explanation:

Second overtone of the wire is same as third harmonic

so its frequency is given as

$f = \frac{3}{2L}\sqrt{\frac{T}{\mu}}$

here we know that

$\mu = \frac{M}{L}$

$\mu = \frac{7.25 \times 10^{-3}}{0.62}$

$\mu = 0.0117 kg/m$

now we have

$f = \frac{3}{2\times 0.62}\sqrt{\frac{3910}{0.0117}}$

$f = 1398.6 Hz$

Now fundamental frequency of sound in a pipe is given as

$f = \frac{v}{4L}$

$1398.6 = \frac{340}{4L}$

$L = 0.06 m$

$L = 6 cm$

7 0

2 years ago

A train is moving with a velocity of 20 m/s. when the brakes are applied the acceleration is reduced to -0.6 m/s².calculate the

Serhud [2]

Answer:

x = 333.33 [m]

Explanation:

To solve this problem we must use the following kinematics equation.

$v_{f}^{2} = v_{i}^{2}-(2*a*x)$

where:

Vf = final velocity = 0

Vi = initial velocity = 20 [m/s]

a = desacceleration = 0.6 [m/s^2]

x = distance [m]

Note: the final speed is zero as the body finishes its movement.

Now replacing:

0 = (20)^2 - (2*0.6*x)

1.2*x = 400

x = 333.33 [m]

3 0

2 years ago