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liq [111]
3 years ago
5

A chemistry student weighs out 0.0975 g of acrylic acid (HCH2CHCO2) into a 250. mL volumetric flask and diluted to the mark with

distilled water. He plans to titrate the acid with 0.0500 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equilvalence point. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Alex17521 [72]3 years ago
8 0

Answer:

27.06 mL.

Explanation:

  • Firstly, we need to calculate the molarity of acrylic acid.

Molarity is the no. of moles of solute dissolved in a 1.0 L of the solution.

M = (no. of moles of acrylic acid)/(V of the solution (L))

M = (mass/molar mass)acrylic acid / (V of the solution (L))

mass of acrylic acid = 0.0975 g, molar mass of acrylic acid = 72.06 g/mol, V of the solution = 250 mL = 0.25 L.

∴ M = (0.0975 g/72.06 g/mol)/(0.25 L) = 0.0054 M.

  • For the acid-base neutralization, we have the role:

The no. of millimoles of acid is equal to that of the base at the neutralization.

<em>∴ (XMV) NaOH = (XMV) acrylic acid.</em>

X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),

M is the molarity.

V is the volume.

  • For NaOH:

X = 1, M = 0.05 M, V = ??? mL.

  • For acrylic acid:

X = 1, M = 0.0054 M, V = 250.0 mL.

∴ V of NaOH = (XMV) acrylic acid/(XM) NaOH = (1)(0.0054 M)(250.0 mL)/(1)(0.05 M) = 27.06 mL.

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2. Increase B

On increasing the amount of B at equilibrium will shift the equilibrium in forward or rightward direction.

3. Increase C

On increasing the amount of C at equilibrium will shift the equilibrium in backward or leftward direction.

4. Decease A

On decreasing the amount of A at equilibrium will shift the equilibrium in backward or leftward direction.

5. Decease B

On decreasing the amount of B at equilibrium will shift the equilibrium in backward or leftward direction.

6. Decease C

On decreasing the amount of C at equilibrium will shift the equilibrium in forward or rightward direction.

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On doubling A and halving B, equilibrium constant of the reaction = K'

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The value of equilibrium constant K' is equal to K, which means that equilibrium will not shift in any direction.

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K=\frac{[C]^2}{[A][B]}

On doubling B and C, equilibrium constant of the reaction = K'

K'=\frac{[2C]^2}{[A][2B]}=\frac{4[C]^2}{[A][2B]}=\frac{2[C]^2}{[A][B]}

K' = 2 K

The value of equilibrium constant K' is double the K, which means that product is increasing which means that equilibrium will shift in backward or leftward direction.

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