If two charged objects each have 2.5 C of charge on them and are located 100 m apart, how strong is the electrostatic force betw
1 answer:
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2.72 N
Explanation:
Step 1:
From the basic formula in electrostatics
F = E * q
where F = Force due to charges
E = Electric field strength
q = Charge
Step 2:
From the given question
q=
E =
F = N
Answer:
Impulse, |J| = 0.6716 kg-m/s
Force, F = 63.35 N
Explanation:
It is given that,
Mass of the baseball, m = 0.146 kg
Initial speed of the ball, u = 15.3 m/s
Final speed of the ball, v = 10.7 m/s
To find,
(a) The magnitude of this impulse.
(b) The magnitude of the average force of the glass on the ball.
Solution,
(a) Impulse of an object is equal to the change in its momentum. It is given by :
J = -0.6716 kg-m/s
or
|J| = 0.6716 kg-m/s
(b) Another definition of impulse is given by the product of force and time of contact.
t = 0.0106 s
F = 63.35 N
Hence, this is the required solution.