Answer:
a)F=3 x 10⁻⁷ N
b)x=2.405 m
Explanation:
Given that
m₁=295 kg
m₂=595 kg
d= 4.1 m
a)
m₃=63 kg
r=d/2 = 2.05 m
The force between the mass m₁ and m₃
by putting the values
F₁₃=2.94 x 10⁻⁷ N
The force between the mass m₂ and m₃
by putting the values
F₂₃=5.94 x 10⁻⁷ N
The net force F
F= F₂₃- F₁₃
F=5.94 x 10⁻⁷ N-2.94 x 10⁻⁷ N
F=3 x 10⁻⁷ N
b)
Lest take at distance x from mass m₂ net force is zero.
Form above two equation
x²=2.01(4.1-x)²
x=1.42 (4.1-x)
x=5.82 - 1.42x
x=2.405 m
Answer:(a)0,(b)1.061 kg-m/s
Explanation:
Given
mass of ball is 0.10 kg
Initial speed is 15 m/s
Maximum height reached by ball is h
final velocity =0
thus momentum of ball at maximum height is 0 as velocity is zero
For halfway to maximum height
where 
v=10.61 m/s
Thus its momentum is
The answer to the question being asked on what do you called when the movement of the bones around a fixed angle without lateral displacement is ROTATION. Rotation movement allows the bone to move in a single long axis without being displaced.
F_x=Fcos(a)
F_y=Fsin(a)
1.F_x=166cos(55)
F_y=166sin(55) (55 because of the supplementary angle)
2.F_x= 575cos(-75) (complimentary angle/negative because its under x-axis)
F_y= 575sin(-75)
The values you get can be negative or positive depending on which side the vector is pointing at.
