Answer:
(a) Radius = 4.6 x 10^11 m
(b) speed = 16.96 km/s
Explanation:
Time period, T = 5.4 earth years
mass of sun, M = 1.989 x 10^30 kg
(a) Let the orbital radius is R.
use the formula of period

(b) Let the speed is v.
Note that Ohm's law is given by
V = IR
Hence, V is 120V and I is 2.2A
Substitute the values:
120 = 2.2R
Therefore, R = 120/2.2
R = 54.5 Ohms
It rises till all of its Kinetic energy is converted into potential energy.
so, mgh=(1/2)m(v^2)
so, h=(v^2)/2g = 12*12/(2*9.81)=7.34 m
Answer:
2.77 * 10^5 m/s
Explanation:
Let us recall that kinetic energy is given by 1/2 mv^2
Where;
m = mass of the body
v = velocity of the body
In this case,
m = 3.38 * 10^31 kg
KE= 1.30 * 10^42 J
KE = 1/2 mv^2
v = √2KE/m
v = √2 * 1.30 * 10^42/3.38 * 10^31
v = √7.69 * 10^10
v = 2.77 * 10^5 m/s