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3 years ago

If a car accelerates from a speed of 10 m/s at an acceleration of 2 m/s2 for 3s.

Physics

1 answer:

Flauer [41]3 years ago

3 0

Answer:

$\boxed{\sf Final \ speed \ of \ the \ car = 16 \ m/s}$

Given:

Initial speed (u) = 10 m/s

Acceleration (a) = 2 m/s²

Time taken (t) = 3s

To Find:

Final speed (v) of the car

Explanation:

From equation of motion we have:

$\boxed{ \bold{v = u + at}}$

By substituting value of u, a & t in the equation we get:

$\sf \implies v = 10 + 2\times 3 \\ \\ \sf \implies v = 10 + 6 \\ \\ \sf \implies v = 16 \: m {s}^{ - 1}$

$\therefore$

Final speed (v) of the car = 16 m/s

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iv. An object is 14 cm in front of a convex mirror. The image is 5.8 cm behind the mirror. What is the focal length of the mirro

Dvinal [7]

Answer:

C. 9.9 cm

Explanation:

The location of the object, u = 14 cm

The location of the image, v = 5.8 cm

The focal length of the mirror, f = Required

The mirror formula for a convex mirror is given as follows;

$\dfrac{1}{u} -\dfrac{1}{v} = -\dfrac{1}{f}$

Therefore, we get;

$\dfrac{1}{14 \ cm} -\dfrac{1}{5.8 \ cm} =- \dfrac{41}{406 \ cm} = -\dfrac{1}{f}$

Therefore;

$f = \dfrac{406 \ cm}{41} \approx 9.9 \ cm$

The focal length of the mirror, f ≈ 9.9 cm

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3 years ago

The purpose of the air filter is to

marishachu [46]

The purpose of an air filter is to purify the air around you removing particles such as dust from the air.

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3 years ago

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In an adiabatic process, what happens when gases in a system are compressed?

I am Lyosha [343]

I would say its c
given a fixed volume, when volume decreases while mass remains constant
density increases ie temperature increases also

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3 years ago

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Please help me with the formular of this question and the solvings.

sweet [91]

Answer:

$\displaystyle T=48.86\ N$

Explanation:

<u>Net Force </u>

The second Newton's law explains how to understand the dynamics of a system where several forces are acting. The forces are vectorial magnitudes which means the x and y coordinates must be treated separately. For each component, the net force must equal the mass by the acceleration, i.e.

$F_{nx}=ma_x$

$F_{ny}=ma_y$

The box with mass m=20 kg is pulled by a rope with a $\theta= 30^o$ angle above the horizontal. It means that force (called T) has two components:

$T_x=Tcos\theta$

$T_y=Tsin\theta$

We'll assume the positive directions are to the right and upwards and that the box is being pulled to the right. There are two forces in the x-axis: The x-component of T (to the right) and the friction force (to the left). So the equilibrium equation for x is

$\displaystyle T\ cos\theta -Fr=m.a$

There are three forces acting in the y-axis: The component of T (upwards), the weight (downwards), and the Normal (upwards). Since there is no movement in the y-axis, the net force is zero and:

$\displaystyle N+T\ sin\theta -mg=0$

Rearranging:

$\displaystyle N+T\ sin\theta =mg$

Solving for N in the y-axis:

$\displaystyle N=mg-T\ sin\theta$

The friction force is given by

$\displaystyle Fr=\mu.N$

Replacing in the equation for the x-axis, we have

$\displaystyle T\ cos\theta -\mu\ N=ma$

Replacing the formula for N in the equation for the x-axis

$\displaystyle T\ cos\theta -\mu(mg-T\ sin\theta)=ma$

Operating and rearranging

$\displaystyle T\ cos\theta -\mu\ mg+T\ \mu\ sin\theta=ma$

$\displaystyle T\ (cos\theta +\mu\ sin\theta)=ma +\mu\ mg$

Solving for T:

$\displaystyle T=\frac{a+\mu\ g}{cos\theta +\mu\ sin\theta }\ m$

Plugging in the given values:

$\displaystyle T=\frac{0.4+0.2(9.8)}{cos30^o+0.2\ sin30^o }\ .20$

$\boxed{\displaystyle T=48.86\ N}$

7 0

2 years ago

Industrial espionage is the use of spying techniques to find out key information that is of economic value.

german

Answer:

The given statement is "True".

Explanation:

Industrial spying or espionage seems to be the surreptitious but sometimes unconstitutional method of trying to investigate competition in the market to gain a competitive advantage throughout the commercial enterprise.
The investigation's goal may be a closely guarded secret including a patented product design or formulation, or growth strategy details.

4 0

3 years ago