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Taya2010 [7]
3 years ago
8

If a car accelerates from a speed of 10 m/s at an acceleration of 2 m/s2 for 3s.

Physics
1 answer:
Flauer [41]3 years ago
3 0

Answer:

\boxed{\sf Final \ speed \ of \ the \ car = 16 \ m/s}

Given:

Initial speed (u) = 10 m/s

Acceleration (a) = 2 m/s²

Time taken (t) = 3s

To Find:

Final speed (v) of the car

Explanation:

From equation of motion we have:

\boxed{ \bold{v = u + at}}

By substituting value of u, a & t in the equation we get:

\sf \implies v = 10  + 2\times 3 \\  \\ \sf \implies v = 10 + 6 \\  \\ \sf \implies v = 16 \: m {s}^{ - 1}

\therefore

Final speed (v) of the car = 16 m/s

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In order to determine the required force to stop the car, proceed as follow:

Calculate the deceleration of the car, by using the following formula:

v^2=v^2_o-2ax

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v: final speed = 0m/s (the car stops)

vo: initial speed = 36m/s

x: distance traveled = 980m

a: deceleration of the car= ?

Solve the equation above for a, replace the values of the other parameters and simplify:

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Replace the previous values and simplify:

F=(820kg)(0.66\frac{m}{s^2})=542.20N

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