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Nady [450]
3 years ago
14

Si la frecuencia de una onda de 12 Hz y su longitud es de 4 metro ¿cuál será su velocidad?

Physics
1 answer:
ella [17]3 years ago
7 0

Answer: srry I don’t understand that language

Explanation:

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Brandon buys a new Seadoo. He goes 22 km north from the beach. He then goes 11km to the east. Then chases a boat 3 km north. Wha
KIM [24]

Answer:

36kms

Explanation:

22+1=33

33+3=36

6 0
3 years ago
Earlier we discussed the concept of isostasy, where lower density rocks rise higher than higher density rocks. How is the variat
Elena L [17]

The variation of water depth at spreading centers (ridges) controlled by isostasy  as convective cooling cools the rocks much more effectively the than heat conduction.

<h3>What is convective heat transfer?</h3>

When heat transfer takes place between the two fluids in direct or indirect contact.

The lithosphere cools when it moves away from the ridge axis by sea floor spreading. The cooler rocks have low density, so the sea floor gets deeper as the lithosphere gets more dense.

Thus, the convective cooling cools the rocks much more effectively the than heat conduction.

Learn more about convective heat transfer

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4 0
2 years ago
What direction does an applied force move an object
monitta
The object will move in the direction of the applied force.
4 0
3 years ago
Read 2 more answers
Define potential energy. Give its mathematical formula and SI unit.
Stels [109]

Answer:

The type of mechanical energy that is possessed due to the virtue of motion or state of a body is known as potential energy.

Its formula: PE= mgh

Its SI unit is joule.

Hope it helps you..

3 0
3 years ago
A constant-volume perfect gas thermometer indicates a pressure of 6.69 kPa at the triple point temperature of water (273.16 K).
mina [271]

Answer:

(a) ΔP=0.0245 kPa

(b) P=9.14 kPa

(c)ΔP=0.0245 kPa

Explanation:

(a) As it is perfect gas we can use

(P₁V₁)/T₁=(P₂V₂)/T₂

Since this constant volume so

P₁/T₁=P₂/T₂

T₂ is change in temperature

T₂=1.00+273.16

T₂=274.16 K

P_{2}=(\frac{6.69}{273.16} )*274.16\\P_{2}=6.71449 kPa

ΔP=6.71449-6.69

ΔP=0.0245 kPa

(b) As

P_{2}=(\frac{6.69}{273.16} )*373.16\\P_{2}=9.14 kPa

(c) Same steps as in part (a)

P_{2}=(\frac{9.14}{373.16} )*374.16\\P_{2}=9.164kPa

ΔP=9.164-9.14

ΔP=0.0245kPa

8 0
3 years ago
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