Answer:
The first solution is (-6, 29), and the second is (4, -11).
Step-by-step explanation:
Rewrite the 2nd equation as y = -4x + 5. Then the first equation becomes:
= -4x + 5 = x^2 - 2x - 19.
This equation has only one variable: x. Rewriting this equation in the standard form of a quadratic, we get:
0 = x^2 + 2x - 24
and this quadratic can be factored into 0 = (x - 4)(x + 6), whose roots are
{-6, 4}. This agrees with one of the two points mentioned in the problem:
(-6, 29) is a solution. What's the other one?
We have just found that the 2 roots are {-6, 4}. Then the missing root is 4, and the y-value there is found from y + 4x = 5:
y = -4x + 5, which here is y = -4(4) + 5, or y = -16 + 5, or y = -11.
The first solution is (-6, 29), and the second is (4, -11).
