The answer is 6.25 x 10^4.
Na = +1
H = +1
O = -2
Total charge is 0:
1 + 1 + C + 3 x -2 = 0
C = 4
About 255.3 grams is the answer I believe. I just had a school work packet and had that question on it, and that is the answer that I had put on it I believe.
<span>In June there are fewer hours of daylight and less direct sunlight in the Southern Hemisphere.
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The mass of air in the scuba tank is 841.614 g.
Using the ideal gas equation;
PV=nRT
P = pressure of the gas = 195 kPa
V = volume of the gas = 350 L
n = Number of moles of the gas = ??
R = molar gas constant = R = 8.314 J K-1 mol-1
T = temperature of the gas = 10 °C or 283 K
n = PV/RT
n = 195 * 350/8.314 * 283
n = 68250/2352.862
n = 29.00 moles
Number of moles = mass/molar mass
mass of air = Number of moles * molar mass
mass of air = 29.00 moles * 29g/mol
Mass of air = 841.614 g
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