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k0ka [10]
3 years ago
6

Which bond is most polar c-o h-o n-o s-o

Chemistry
1 answer:
scZoUnD [109]3 years ago
6 0

Answer:

Option 4 with o-h in the most polar bond, since the two atoms in the bond have the greatest difference in electronegativity.  This is assuming there are no other factors in other atoms bound to either of the elements in the bond.

Explanation:

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How does the mass of a gas particle affect its rate of effusion?
ryzh [129]
The mass of gas particle affects the rate of effusion by decreasing the rate as the mass increases. This describe by the Graham's Law of Effusion where the rate of effusion is inversely proportional to the square root of the molar mass of a substance. Hope this helps.
4 0
3 years ago
Gold (Au) is considered a(n)<br><br><br> Compound<br><br> Potatoes<br><br> Mixture<br><br> Element
strojnjashka [21]

Answer:

Element

Explanation:

The symbol for gold is Au which only has one capital letter. This means that there is only one thing that makes up gold which would make it an element.

hope this helps :)

3 0
3 years ago
What is the change in the freezing point of water when 35.0 g of sucrose is
frez [133]

From the calculations, we can see that, the change in the freezing point is -0.634°C.

<h3>What is freezing point?</h3>

The term freezing point refers to the temperature at which a liquid is changed to solid.

Given that;

ΔT = K  m i

Number of moles sucrose = 35.0 g/ 342.30 g/mol = 0.1 moles

molality =  0.1 moles/ 300.0 * 10^-3 Kg

= 0.33 m

Thus;

ΔT = -1.86°C/mol *  0.33 m * 1

= -0.634°C

Learn more about freezing point:brainly.com/question/3121416

#SPJ1

3 0
2 years ago
1.
Leya [2.2K]

Answer:

V₂ = 530.5 mL

Explanation:

Given data:

Initial temperature = 20.0°C

Final temperature = 40.0 °C

Final volume = 585 mL

Initial volume = ?

Solution:

Initial temperature = 20.0°C (20+273 = 293 K)

Final temperature = 40.0 °C (40+273 = 323 K)

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂  

V₂ = 585 mL × 293 K / 323 K

V₂ = 171405 mL.K / 323 K

V₂ = 530.5 mL

6 0
3 years ago
The molar mass of an unknown gas was measured by an effusion experiment. It was found that it took 60 s for the gas to effuse, w
Marizza181 [45]

Answer:

The molar mass of the gas is 44 g/mol

Explanation:

It is possible to solve this problem using Graham's law that says: Rates of effusion are inversely dependent on the square of the mass of each gas. That is:

\frac{r_1}{r_2} =\frac{\sqrt{M_2} }{\sqrt{M_1} }

If rate of effusion of nitrogen is Xdistance / 48s and for the unknown gas is X distance / 60s and mass of nitrogen gas is 28g/mol (N₂):

\frac{X/48s}{X/60s} =\frac{\sqrt{M_2} }{\sqrt{28g/mol} }

6,61 = √M₂

44g/mol = M₂

<em>The molar mass of the gas is 44 g/mol</em>

<em></em>

I hope it helps!

4 0
3 years ago
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