Explanation:
The kinetic energy is basically the energy possesses by virtue of a body's motion
1. The truck moving to the quarry
let the mass be x
and the velocity is given as 20m/s
we know that the kinetic energy is given as
KE=1/2mv^2
KE=1/2(x)*20^2
KE=1/2(x)400
KE=200x
2. The truck leaving to the quarry
let the mass be 2x
and the velocity is given as 20m/s
we know that the kinetic energy is given as
KE=1/2mv^2
KE=1/2(2x)*20^2
KE=1/2(2x)400
KE=400x
From the analysis the kinetic energy is a function of mass, doubling the mass doubles the kinetic energy
<span>The answer is 15 centimeters. The waves with the
smallest wavelengths (also highest
frequency) have the least capacity to diffract around objects hence have a
shadowing effect, behind the object, especially if the wavelength is small
compared to the object. This is also the reason why high-frequency electromagnetic waves do not have a good reach in mountainous
regions. </span>
Total work energy on the input side is WE = Fs; where F is a force acting on a mass to push it s distance. This is the so-called work function. Let fs = we, which is the work energy (useful energy) attained as output when WE is input.
<span>From the conservation of energy WE = Fs = fs - kNs = Total Output energy. Net force f = F - kN where kN is friction force acting against the pushing (input) force F. In the real world, there is always friction at some level. That is kN > 0 always. </span>
<span>Thus Fs = (F - kN)s; kNs = the energy lost to friction where k is the friction coefficient and N is the normal force on the surface(s) where the friction is generated. By definition, efficiency = fs/Fs = useful work/work input. Clearly fs = Fs - kN < Fs . Thus efficiency = fs/Fs < 1.00, which means output fs < Fs the input whenever kN > 0, which in the real world it always is. </span>
<span>The short answer is...output is always less than input because of friction and, sometimes, other losses like wind drag (which is a form of friction anyway).</span>
Answer:
•2 kilometres.................
Answer:
Pam's velocity when she crosses the finish line is 10 m/s.
Explanation:
Given;
initial velocity of Pam, u = 3.3 m/s
acceleration of Pam, a = 3 m/s²
last distance covered, d = 15 m
let her final velocity = v
Apply the following kinematic equation to determine Pam's final velocity;
v² = u² + 2ad
v² = 3.3² + 2(3)(15)
v² = 10.89 + 90
v² = 100.89
v = √100.89
v = 10 m/s
Therefore, Pam's velocity when she crosses the finish line is 10 m/s.