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densk [106]
4 years ago
6

STATE THE HOOKE'S LAW

Physics
2 answers:
victus00 [196]4 years ago
6 0
The Hooke's law is a principal of physics that states that the force needed to extend or compress a spring by some distance x scales linearly with respect to that distance.
Anvisha [2.4K]4 years ago
6 0

a law stating that the strain in a solid is proportional to the applied stress within the elastic limit of that solid.


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A roller-coaster car has a mass of 1040 kg when fully loaded with passengers. As the car passes over the top of a circular hill
rusak2 [61]

Answer:

a.6373.5 N

b.-3837.6 N

Explanation:

Mass of roller coaster=m=1040 kg

Radius=r=24 ,

a.v=9.4m/s

Normal force=F_N

According to question

mg-F_N=\frac{mv^2}{r}

Where g=9.81 m/s^2

Substitute the values

1040\times 9.81-F_N=\frac{1040\times (9.4)^2}{24}

10202.4-F_N=3828.9

F_N=10202.4-3828.9=6373.5 N

b.v=18m/s

g=9.81 m/s^2

1040\times 9.81-F_N=\frac{1040\times (18)^2}{24}

10202.4-F_N=14040

F_N=10202.4-14040=-3837.6 N

8 0
4 years ago
The Nardo ring is a circular test track for cars. It has a circumference of 12.5 km. Cars travel around the track at a constant
KIM [24]

Answer: 50 km, 0, 27.78 m/s

Explanation:

Given

Circumference of the track is 12.5\ km

Speed of car is 100\ km/h

Car drives for 30\ \text{minute}\ or\ 0.5\ hr

(a)Distance traveled is

\Rightarrow D=100\times 0.5\\\Rightarrow D=50\ km

(b)displacement of the car

It can be observed that 12.5 is a multiple of 50, that is, 50 km can be interpreted as 4 complete rounds of the track.

Therefore, the displacement of the car is zero.

(c)To convert kmph to m/s, multiply the entity by \frac{5}{18}

\Rightarrow 100\times \dfrac{5}{18}\\\\\Rightarrow 27.78\ m/s

5 0
3 years ago
Assume you push a 20 kg child in a little red wagon with a force of 100 N. However, the dirt and rocks below the wheels
GenaCL600 [577]

Answer:

a

Explanation:

4 0
3 years ago
Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.
lina2011 [118]

Answer:

-6.0 m/s, 10.4 m/s

Explanation:

To find the x- and y- components, we have to apply the formulas:

v_x = v cos \theta

v_y = v sin \theta

where

v = 12.0 m/s is the magnitude of the vector

\theta is the angle between the direction of the vector and the positive x-axis

Here, the angle given is the angle above the negative x-axis; this means that the angle with respect to the positive x-axis is

\theta=180^{\circ} - 60^{\circ} = 120^{\circ}

So, the two components are:

v_x = (12.0 m/s) cos 120^{\circ}=-6.0 m/s

v_y = (12.0 m/s) sin 120^{\circ}=10.4 m/s

5 0
3 years ago
Which sound is most likely the most intense
MrMuchimi
Are there answers choice or a picture I can see?
4 0
4 years ago
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