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3 years ago

7

Which question requires the collection of data to answer it?

1 answer:

iren [92.7K]3 years ago

3 0

Answer:

a

Explanation:

b, c, and d are all opinion based, a is the only one that you need factual evidence and observations.

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At the moment a hot cake is put in a cooler, the difference between the cakes and the cooler's

hram777 [196]

Answer: D(t)= 50(4/5)^t

Explanation: If 1/5 of the temperature difference is lost each minute, that means 4/5 of the difference remains each minute. So each minute, the temperature difference is multiplied by a factor of 4/5 (or 0.8).

If we start with the initial temperature difference, 50° Celsius, and keep multiplying by 4/5, this function gives us the temperature difference t minutes after the cake was put in the cooler.

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3 years ago

Read 2 more answers

Weak magnetic fields can be measured at the surface of the brain. Although the currents causing these fields are quite complicat

STALIN [3.7K]

To develop this problem it is necessary to apply the concepts related to a magnetic field in spheres.

By definition we know that the magnetic field in a sphere can be described as

$B = \frac{\mu_0}{2}\frac{Ia^2}{(z^2+a^2)^{3/2}}$

Where,

a = Radius

z = Distance to the magnetic field

I = Current

$\mu_0 =$ Permeability constant in free space

Our values are given as

$D=2a = 16cm \rightarrow$ diameter of the sphere then,

$a = 0.08m$

Thus z = a

$B = \frac{\mu_0}{2}\frac{Ia^2}{(a^2+a^2)^{3/2}}$

$B = \frac{\mu_0I}{2(2^{3/2})a}$

$B = \frac{\mu_0 I}{2^{5/2}a}$

Re-arrange to find I,

$I = \frac{2^{5/2}Ba}{\mu_0}$

$I = \frac{2^{5/2}(3*10^{-12})(8*10^{-2})}{4\pi*10^{-7}}$

$I = 1.08*10^{-6}A$

Therefore the current at the pole of this sphere is $1.08*10^{-6}A$

5 0

3 years ago

1. Viruses are unique among infectious agents because they are

yuradex [85]

1,) C

2,) C

Hope this helps

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3 years ago

The instantaneous velocity of an object is the Blank of the object with a Blank.

Ghella [55]

The intaneuos velocity of an object is the

8 0

3 years ago

Calculate the linear momentum for each of the following cases. (a) A proton with mass 1.67 ✕ 10-27 kg moving with a velocity of

Oliga [24]

Answer:

$8.4168\times 10^{-21}\ kgm/s$ upward

4.725 kgm/s to the right

468.6 kgm/s southwest

$1.782\times 10^{49}\ kgm/s$ forward

Explanation:

When the mass of an object is multiplied by its velocity we get momentum

m = Mass

v = Velocity

Proton

$p=mv\\\Rightarrow p=1.67\times 10^{-27}\times 5.04\times 10^6\\\Rightarrow p=8.4168\times 10^{-21}\ kgm/s$

The momentum of the proton is $8.4168\times 10^{-21}\ kgm/s$ upward

Bullet

$p=mv\\\Rightarrow p=0.015\times 315\\\Rightarrow p=4.725\ kgm/s$

The momentum of the bullet is 4.725 kgm/s to the right

Sprinter

$p=mv\\\Rightarrow p=71\times 6.6\\\Rightarrow p=468.6\ kgm/s$

The momentum of the sprinter is 468.6 kgm/s southwest

Earth

$p=mv\\\Rightarrow p=5.98\times 10^{24}\times 2.98\times 10^4\\\Rightarrow p=1.782\times 10^{29}\ kgm/s$

The momentum of the sprinter is $1.782\times 10^{29}\ kgm/s$ forward

4 0

3 years ago