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DedPeter [7]
2 years ago
12

A farm tractor tows a 3300-kg trailer up a 14" incline with a steady speed of 2.8 m/s. what force does the tractor exert on the

trailer ( ignore friction.)
Physics
1 answer:
gladu [14]2 years ago
7 0

The force exerted by gravity is:

F = m g

F = 3300 kg * 9.8 m/s^2

F = 32,430 N

 

The force exerted due to the inclined plane is:

F tractor = 32,430 N * sin 14

<span>F tractor = 7,823.75 N      (answer)</span>

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Answer:

ρ/ρ2 = 3 / R₀       the two densities are different

Explanation:

Density is defined as

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Let's replace

      ρ = A / (4/3 π R₀³)

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b)

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The area of ​​a sphere is

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     ρ2 = F / 4π R₀²

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Atomic number is the number of protons in the nucleon in not very heavy nuclei. This number is equal to the number of neutrons, but changes in heavier nuclei, there are more neutrons than protons.

Let's look for the relationship of the two densities

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     ρ/ρ2 = 3 / R₀

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Making m the subject of the formula, we can find the change in mass to be

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There fore, the amount of mass that needs to be converted to release that amount of energy is 1.122 X 10 ^-7 kg

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