Question

Find the work w1 done on the block by the force of magnitude f1 = 60.0 n as the block moves from xi = -3.00 cm to xf = 1.00 cm

Answer 1

By definition, the work done by a force is given by:
 $W1 = F1 * d$
 Where,
 F: magnitude of force
 d: distance traveled.
 Substituting values we have:
 $W1 = F1 * (xf - xi) W1 = 60 * (0.01 - (-0.03))$
 $W1 = 60 * (0.01 + 0.03) W1 = 60 * (0.04) W1 = 2.40 J$
 Answer: 
 the work w1 done on the block by the force of magnitude f1 = 60.0 n is:
 W1 = 2.40 J