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Triss [41]
3 years ago
7

A sled of mass 8 kg slides along the ice. It has an initial speed of 4 m/s but

Physics
1 answer:
marysya [2.9K]3 years ago
6 0

As our story begins, the sled ... whose mass is 8 kg ...  is sliding along the ice at a speed of 4 m/s.

The sled's kinetic energy is (1/2 m v²) = (4 kg · 16 m²/s²) = 64 J .

After what seems like only the blink of an eye, the sled is no longer sliding.  It is stationary.  Motionless.  At Rest.  Just sitting there !  

Its speed has been reduced to zero and ... because kinetic energy is the energy of motion ... the sled's kinetic energy is now also zero.  Sixty-four Joules of energy have disappeared !

How can this be ? ! ? We know that energy is conserved.  It can never just appear out of nothing, and it can never just disappear into nothing.  If energy suddenly appears, it had to come from somewhere, and if energy suddenly disappears, it had to go somewhere.  So where did our 64 Joules of kinetic energy go ?

It went into the ice, THAT's where !  We can say that the sled did 64J of work, and melted a thin slick layer of water on the surface of the ice.  OR we can say that friction did NEGATIVE 64J of work on the sled, to cancel the 64J that it had originally, sap its kinetic energy, and bring it to rest.

I think <em>choice-B</em> was supposed to say "<em>B. -64J</em>", but somebody typed it sloppily and neglected to proofread it before posting.

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How fast was the storm that hit Galveston and how men died?​
vodomira [7]

Answer:

The storm was a category 4 hurricane that struck Galveston, Texas, on September 8, 1900, bringing winds of 130 miles (210 km) per hour and high tides that overwhelmed the low-lying coastal city, demolishing buildings and claiming more than 8,000 lives.

00p- now I can actually answer :)

Hope that I helped you a little :0

3 0
3 years ago
a man weighs 600 n while on the surface of earth. if he is transported to the planet mythos which has the same mass as earth but
faltersainse [42]

Answer:

24N

Explanation:

Calculation for what his weight would be

Let his WEIGHT on the surface of earth be 600 and Let the RADIUS be 25 which is (5^²) because we were told that the radius is FIVE TIMES larger than earths

Now let calculate his weight using this formula

Weight=Weight on Earth/Radius

Let plug in the formula

Weight=600N/5^²

Weight=600N/25

Weight=24N

Therefore his weight would be 24N

3 0
3 years ago
What would be the diameter of the earth if it had the density of a neurton star
Marat540 [252]
The entire mass of the Earth at neutron star density would fit into a sphere of 305 m in diameter
5 0
3 years ago
The amount of water on earth now is the same as when dinosaurs existed. True or false? PLEASEEEEE HELPPPPPP
Mnenie [13.5K]

Answer: True

Explanation: Because of the way this water cycle has always circulated our planet, there is indeed a chance that the water in your glass is the same water that thirsty dinosaurs were drinking about 65 million years ago

5 0
3 years ago
Read 2 more answers
What is its diameter when the temperature is raised to 100 degrees Celsius? (b) What temperature change is required to increase
alexandr1967 [171]

The question is incomplete, the complete question is;

A spherical steel ball bearing has a diameter of 2.540cm at 25.00∘C.

(a) What is its diameter when it's temperature is raised to

100∘C?

(b) What temperature change is required to increase its volume by

1.000% ?

Answer:

a) 2.542 cm

b) 303.03°C

Explanation:

Given;

Diameter of the ball= 2.540cm

Initial temperature= 25.0°C

Final temperature= 100.0°C

Percentage increase in volume = 1.000%

Temperature coefficient of expansion for steel =11.0×10^−6/∘C

d2= d1[1 + α(T2-T1)]

d2= 2.540[1 + 11.0×10^−6(100-25)]

d2= 2.540[1 + 8.25×10^-4]

d2= 2.542 cm

From;

%V ×1/100 = V ×3α ×∆T/ V

Substituting values;

1.000 ×1/100= 3× 11.0×10^−6 × ∆T

∆T= 0.01/3× 11.0×10^−6

∆T= 303.03°C

4 0
3 years ago
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