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3 years ago

Which best contrasts the weak force and the electromagnetic force??

2 answers:

6 0

Electromagnetic Force
This is the force which exists between all particles which have an electric charge. For example, electrons (negative charge) bind with nucleus of an atom, due to the presence of protons (positive charge). The force is long range, in principle extending over infinite distance.

The Weak Force This force is responsible for nuclear beta decay and other similar decay processes involving fundamental particles. The range of this force is smaller than 1 fm and is 10-7 weaker than the strong force.

Both of the forces are in wave form

katrin [286]3 years ago

3 0

Answer:

The range and the strength

Explanation:

The electromagnetic force is the force that acts between objects with electrical charge, while the weak force is the force responsible for the decay of some particles.

While the electromagnetic force has an infinite range, the weak force has an extremely small range, approximately $10^{-18} m$ .

Another important difference between the two forces is their relative force: while the electromagnetic interaction is the strongest of all four forces (relative strength: 1), the weak interaction is much more weak (relative strength compared to the electromagnetic force: $10^{-6}$ , so it is $10^6$ times weaker than the electromagnetic force.

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Which of the following statements describe the transfer of energy?

Lady_Fox [76]

The answer should be A weighlifter lifting 100lb. bell bar from his chest to a certain height.

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2 years ago

This exercise uses the radioactive decay model. After 3 days a sample of radon-222 has decayed to 58% of its original amount. (a

Vadim26 [7]

Answer: a) 3.85 days

b) 10.54 days

Explanation:-

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = ?

t = time taken for decomposition = 3 days

a = let initial amount of the reactant = 100 g

a - x = amount left after decay process = $\frac{58}{100}\times 100=58g$

First we have to calculate the rate constant, we use the formula :

Now put all the given values in above equation, we get

$k=\frac{2.303}{3}\log\frac{100}{58}$

$k=0.18days^{-1}$

a) Half-life of radon-222:

$t_{\frac{1}{2}}=\frac{0.693}{k}$

$t_{\frac{1}{2}}=\frac{0.693}{0.18}=3.85days$

Thus half-life of radon-222 is 3.85 days.

b) Time taken for the sample to decay to 15% of its original amount:

where,

k = rate constant = $0.18days^{-1}$

t = time taken for decomposition = ?

a = let initial amount of the reactant = 100 g

a - x = amount left after decay process = $\frac{15}{100}\times 100=15g$

$t=\frac{2.303}{0.18}\log\frac{100}{15}$

$t=10.54days$

Thus it will take 10.54 days for the sample to decay to 15% of its original amount.

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3 years ago

When an electron loses or gains a charge, it becomes?

suter [353]

Answer:

It becomes an Ion with either positive or negative charge

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2 years ago

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With energy, changes in the physical world are possible. These can be a change in speed, a change in direction, a change from co

laiz [17]

True because energy can change its speed because of temperature and also its direction

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3 years ago

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A small logo is embedded in a thick block of crown glass (n = 1.52), 4.70 cm beneath the top surface of the glass. The block is

harkovskaia [24]

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

$d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})$

Where,

$d_g =$ Depth of glass

$n_w =$ Refraction index of water

$n_g =$ Refraction index of glass

$n_{air} =$ Refraction index of air

$d_w =$ Depth of water

I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

$d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})$

$d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})$

$d'w = 4.041cm$

Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

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3 years ago