Answer:
D
Explanation:
By law of conservation of momentum:
momentum before collision = momentum after collision
Initial speed of bullet is unknown whereas initial speed of pendulum will be zero as it was at rest.
Final speed of bullet and pendulum will be equal as bullet is embedded in pendulum and both moves together a vertical distance of 6.89cm.
Using third equation of motion:
where:
Thus by placing values 
this speed will be final speed of collision for the calculation of initial speed of bullet.
Putting values:
This 224m/s = 0.224Km/s which is closest to D
Answer:
=
Explanation:
given data:
Pressure P = 3 * 10^ 5 Pa
speed v = 5 m / s
Area A = A
from the information given in equation final Area is 1/3 of initial area i.e.
A ' = A / 3
we know that density of water = 1000 kg / m^ 3
from continuity equation
Av = A ' v'
so we have
speed v ' = 3*A*v / A
v ' = 3*A*5/ A
v = 15 m / s
from bernoulli's equation we can calculate final pressure
Required pressure P ' = P + ( 1/ 2) \rho [ v^ {2} v'^{ 2}]
= ![P ' = P + ( 1/ 2) \rho_{water} [ v^ {2} - v'^{ 2}]](https://tex.z-dn.net/?f=P%20%27%20%3D%20P%20%2B%20%28%201%2F%202%29%20%5Crho_%7Bwater%7D%20%5B%20v%5E%20%7B2%7D%20-%20v%27%5E%7B%202%7D%5D)
=
= 
=
Velocity velocity is a vector value and needs not only the magnitude (speed) but also a direction(west)
Answer:
31.6 m/s
Explanation:
Mass is conserved, so the mass flow at the outlet of the pump equals the mass flow at the nozzle.
m₁ = m₂
ρQ₁ = ρQ₂
Q₁ = Q₂
v₁A₁ = v₂A₂
v₁ πd₁²/4 = v₂ πd₂²/4
v₁ d₁² = v₂ d₂²
Now use Bernoulli equation:
P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂
Since h₁ = 0 and P₂ = 0:
P₁ + ½ ρ v₁² = ½ ρ v₂² + ρgh₂
Writing v₁ in terms of v₂:
P₁ + ½ ρ (v₂ d₂²/d₁²)² = ½ ρ v₂² + ρgh₂
P₁ + ½ ρ (d₂/d₁)⁴ v₂² = ½ ρ v₂² + ρgh₂
P₁ − ρgh₂ = ½ ρ (1 − (d₂/d₁)⁴) v₂²
Plugging in values:
579,160 Pa − (1000 kg/m³)(9.8 m/s²)(15 m) = ½ (1000 kg/m³) (1 − (1.99 in / 3.28 in)⁴) v₂²
v₂ = 31.6 m/s
The answer is Density !, Do you also need an example ?
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