A player kicks a soccer ball in a high arc toward the opponent's goal. When the soccer ball reaches its maximum height, how does
1 answer:
Answer:
The speed of the soccer ball at height point is less than its initial speed
Explanation:
The initial velocity of the soccer can be written in vector form as
= v cos θ î + v sin θ j
where is initial velocity of the ball
v is the initial speed of the ball
Assume soccer ball is kicked at an angle θ with an horizontal and initial speed vm/s. Its horizontal component will be as,
= v cos θ
= v sin θ
At the maximum height, the vertical component becomes zero. therefore, the velocity of the soccer at the maximum point can be written as,
= v cos θ j
where, is velocity of the soccer ball at maximum height
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Answer:
t = 1.41 sec.
Explanation:
If we assume that the acceleration of the blocks is constant, we can apply any of the kinematic equations to get the time since the block 2 was released till it reached the floor.
First, we need to find the value of acceleration, which is the same for both blocks.
If we take as our system both blocks, and think about the pulley as redirecting the force simply (as tension in the strings behave like internal forces) , we can apply Newton's 2nd Law, as they were moving along the same axis, aiming at opposite directions, as follows:
F = m₂*g - m₁*g = (m₁+m₂)*a (we choose as positive the direction of the acceleration, will be the one defined by the larger mass, in this case m₂)
⇒ a = ( = g/5 m/s²
Once we got the value of a, we can use for instance this kinematic equation, and solve for t:
Δx = 1/2*a*t² ⇒ t² = (2* 1.96m *5)/g = 2 sec² ⇒ t = √2 = 1.41 sec.