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Rzqust [24]
3 years ago
15

1).which of the following describes the interaction between a south pole and a north pole of a magnet

Physics
1 answer:
kumpel [21]3 years ago
6 0

1) a) attract

The magnetic force between two magnetic poles is attractive for two unlike poles and repulsive for two like poles. Therefore we have:

1- For two north poles, the force between them is repulsive

2- For two south poles, the force between them is repulsive

3- For a north pole and a south pole, the force between them is attractive

In this problem, we are in the situation described in 3), so the force between the poles is attractive.

2) a) motion of electrons

While electric fields are produced by static electric charges, magnetic fields are produced by charges in motion (currents). In particular, a current in a wire (where a current is simply the motion of electrons inside the wire) produces a magnetic field whose intensity is

B=\frac{\mu_0 I}{2 \pi r}

where

I is the current in the wire

r is the radial distance from the wire

And the direction of the field lines are such that the field form concentric circles around the wire.

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A water bath in a physical chemistry lab is 1.55 m long, 0.710 m wide, and 0.570 m deep (high). If it is filled to within 3.55 i
Lesechka [4]

Answer:

528 liter.

Explanation:

Volume of the tank(cuboid) = l*b*h

But volume of the water = l*b*h

Where

l= length of the tank

b = width of the tank

h = the length from the bottom of the tank,

3.55 in to m,

0.09017m

Length of the water in the tank = 0.570 - 0.09017

= 0.47983 m.

Volume = 0.47983*0.710*1.55

= 0.528 m3.

1 m3 = 1000 liter.

0.528 m3 = 0.528*1000

= 528 liter

7 0
3 years ago
How many new facilities does an average facility manager build during his or her career?
wlad13 [49]

An average facility manager can build one new facility during his or her career.

 

<span>A </span>facilities manager<span> is the ultimate organiser, making sure that a workplace meets the needs of employees by managing all of the required services. In this job, you will be responsible for the </span>management<span> of services and processes that support the core business of an organisation.</span>

8 0
3 years ago
skater spins over a point at a speed of 3.0 rotations per second then the momentum of inertia is 0.60 kg.M2, what is its angular
laiz [17]

Answer:

L=11.3\ kg-m^2/s

Explanation:

Given that,

Angular speed of a skater, \omega=3\ rot/s=18.84\ rad/s

The moment of inertia of the skater, I = 0.6 kg-m²

We need to find the angular momentum of the skater. The formula for the angular momentum of the skater is given by :

L=I\omega

Substitute all the values,

L=0.6\times 18.84\\\\L=11.3\ kg-m^2/s

So, its angular momentum is equal to 11.3\ kg-m^2/s.

8 0
3 years ago
The pressure of a gas changes from 120 kPa. The volume changes from 45 L to 40 L. If the initial temperature is 81 c, what is th
irina [24]

Explanation:

we are not given the pressure change, check yhe question please

7 0
3 years ago
You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t
Sladkaya [172]

Answer:

0.767

Explanation:

The work done on the truck by the frictional drag force is given by

W=-Fd

where

F is the magnitude of the frictional force

d = 38.0 m is the maximum displacement allowed for the truck

The negative sign is due to the fact that the force of friction is opposite to the motion of the truck

The force of friction can also be written as:

F=\mu mg

where

\mu is the coefficient of kinetic friction between the truck and the lane

m is the mass of the truck

g is the acceleration of gravity

So we can rewrite the work done as

W=-\mu mg d (1)

According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the truck:

W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2 (2)

where

v = 0 is the final velocity of the truck

u = 23.9 m/s is the initial velocity of the truck

By combining (1) and (2) we get

-\frac{1}{2}mu^2 = -\mu mg d

And solving for \mu, we find the minimum coefficient of kinetic friction able to stop the truck in a distance d:

\mu = \frac{u^2}{2gd}=\frac{23.9^2}{2(9.8)(38.0)}=0.767

7 0
3 years ago
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