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Rzqust [24]
3 years ago
15

1).which of the following describes the interaction between a south pole and a north pole of a magnet

Physics
1 answer:
kumpel [21]3 years ago
6 0

1) a) attract

The magnetic force between two magnetic poles is attractive for two unlike poles and repulsive for two like poles. Therefore we have:

1- For two north poles, the force between them is repulsive

2- For two south poles, the force between them is repulsive

3- For a north pole and a south pole, the force between them is attractive

In this problem, we are in the situation described in 3), so the force between the poles is attractive.

2) a) motion of electrons

While electric fields are produced by static electric charges, magnetic fields are produced by charges in motion (currents). In particular, a current in a wire (where a current is simply the motion of electrons inside the wire) produces a magnetic field whose intensity is

B=\frac{\mu_0 I}{2 \pi r}

where

I is the current in the wire

r is the radial distance from the wire

And the direction of the field lines are such that the field form concentric circles around the wire.

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(a) The distance to a star is approximately 8.64 ✕ 1018 m. If this star were to burn out today, in how many years would we see i
spayn [35]

Answer:

A. 922 yrs

B. 8.21mins

C. 2.56 seconds

Explanation:

Pls refer to attached file

7 0
3 years ago
Read 2 more answers
A bicycle has wheels of radius 0.320 m. Each wheel has a rotational inertia of 0.0800 kg⋅m2 about its axle. The total mass of th
Ad libitum [116K]

Answer:

\frac{K_{rot}} {K_T} = 0.019

Explanation:

We know that Rotational Kinetic Energy is given by,

K_{rot}=\frac{1}{2}Iw^2

Where I is the inertia and w the angular velocity. We know as well thatw= \frac{v}{r}

The we can replace,

K_{rot} = \frac{1}{2}I(\frac{v}{r})^2

K_{rot} = \frac{1}{2}I(\frac{v^2}{r^2})

That equation are perfect for the 4 wheel, however we need a similar expresion for the ycycle

K_{tran} = \frac{1}{2}mv^2

The total energy can be expressed as follow,

K_T = K_{rot}+K{tran}

K_T=2(\frac{1}{2}I\frac{v^2}{r^2})+\frac{1}{2}mv^2

Whit this expression is easy to find te ratio of rotational kinetic energy, we need to make the relation between K_{rot} \Rightarrow K_T

\frac{K_{rot}} {K_T} = \frac{2I}{2I+mr^2}(You only need to put the previous values and simplify)

Substituting I=0.08kg.m^2, m=79kg and r=0.32m

We have

\frac{K_{rot}} {K_T} = \frac{2I}{2I+mr^2} \\\frac{K_{rot}} {K_T} = \frac{2(0.08)}{2(0.08)+(79)(32)}

\frac{K_{rot}} {K_T} = 0.019

4 0
3 years ago
How do physicists use science?
Ksju [112]

Answer:B, They preform experiments.

Explanation:

your welcome :)

6 0
3 years ago
Which answer accurately describes the difference between speed and velocity?
devlian [24]

Speed only requires distance. Velocity requires direction.

AS speed is scalar quantity and have only magnitude of distance covered .

But velocity is a vector quantity.To describe completely  direction is also required alongwith magnitude of distance.

6 0
4 years ago
A revolutionary war cannon, with a mass of 2260 kg, fires a 21 kg ball horizontally. The cannonball has a speed of 105 m/s after
Marrrta [24]

Answer:

0.97566 m/s

Explanation:

m_1 = Mass of cannon = 2260 kg

v_1 = Velocity of cannon

m_2 = Mass of ball = 21 kg

v_2 = Velocity of ball = 105 m/s

As the momentum of the system is conserved we have

m_1v_1=m_2v_2\\\Rightarrow v_1=\dfrac{21\times 105}{2260}\\\Rightarrow v_1=0.97566\ m/s

The velocity of the cannon is 0.97566 m/s

7 0
4 years ago
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