A 1.25 m long pendulum on Mars

A rigid tank initially contains 3kg of carbon dioxide (CO2) at a pressure of 3bar.The tank is connected by a valve to a friction

marissa [1.9K]

Answer:

Part a: The total amount of energy transfer by the work done is 54.81 kJ.

Part b: The total amount of energy transfer by the heat is 54.81 kJ

Explanation:

Mass of Carbon Dioxide is given as m1=3 kg

Pressure is given as P1=3 bar =300 kPA

Volume is given as V1=0.5 m^3

Pressure in tank 2 is given as P2=2 bar=200 kPa

T=290 K

Now the Molecular weight of $CO_2$ is given as

M=44 kg/kmol

the gas constant is given as

$R=\frac{\bar{R}}{M}\\R=\frac{8.314}{44}\\R=0.189 kJ/kg.K$

Volume of the tank is given as

$V=\frac{mRT}{P_1}\\V=\frac{3 \times 0.189 \times 290}{300 }\\V=0.5481 m^3$

Final mass is given as

$m_2=\frac{P_2V}{RT}\\m_2=\frac{200\times 0.5481}{0.189\times 290}\\m_2=2 kg$

Mass of the CO2 moved to the cylinder

$m=m_1-m_3\\m=3-2=1 kg$

The initial mass in the cylinder is given as

$m_{(cyl)_1}=\frac{P_{(cyl)_1}V_1}{RT}\\m_{(cyl)_1}=\frac{200\times 0.5}{0.189 \times 290}\\m_{(cyl)_1}=1.82 kg$

The mass after the process is

$m_{(cyl)_2}=m_{(cyl)_1}+m\\m_{(cyl)_2}=1.82+1\\m_{(cyl)_2}=2.82\\$

Now the volume 2 of the cylinder is given as

$V_{(cyl)_2}=\frac{m_{(cyl)_2}RT}{P_2}\\m_{(cyl)_2}=\frac{2.82\times 0.189\times 290}{200}\\m_{(cyl)_1}=0.774 m^3$

Part a:

So the Work done is given as

$W=P(V_2-V_1)\\W=200(0.774-0.5)\\W=54.81 kJ$

The total amount of energy transfer by the work done is 54.81 kJ.

Part b:

The total energy transfer by heat is given as

$Q=\Delta U+W\\Q=0+W\\Q=54.81 kJ$

As the temperature is constant thus change in internal energy is 0.

The total amount of energy transfer by the heat is 54.81 kJ

7 0

3 years ago

A metal ring 4.20 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpend

andrezito [222]

Answer:

Explanation:

We have a metal ring of diameter

d = 4.2cm = 0.042m

r = d/2 = 0.021m

And it is place between the north pole and south pole of a large magnet with the plane of it's area perpendicular to the magnetic field.

Given that the magnetic field is

B = 1.12 T

The rate of decrease of magnetic field is 0.2T/s, since it is decrease then,

dB/dt = -0.2 T/s

The induce electric field is given as,

From faradays law

ε = ∫E•dl = -dΦ/dt

Magnetic flux is given as

Φ = BA

Φ = πr²×B = πr²B

Also, ∫E•dl = E×2πr = 2πrE

So,

∫E•dl = -dΦ/dt

2πrE = -d(πr²B) / dt

r is a constant, then

2πrE = -πr² dB/dt

Divide both side by πr

2E = -r dB/dt

E = -r dB/dt / 2

E = -0.021 × -0.2 / 2

E = 0.0021 V/m

The magnetic field point from north to south pole and it is decreasing and this means that the magnetic flux is also decreasing, so the induce magnetic field must point in the same direction of the original magnetic field, so the induce current circulate counter-clockwise as viewed from the south pole

5 0

3 years ago

What happens if you drop a chicken wing from the top of the Eiffel Tower

horsena [70]

Answer:

It either goes WEEEEEEE. Or it just breaks apart.

Explanation:

4 0

2 years ago

Read 2 more answers

What is the answer to this question?

solmaris [256]

Answer:

NA2SO3 is the reactant in the reaction

Explanation:

The substances which take part in a chemical reaction are called reactants

HOPE IT HELPS 

HAVE A NICE DAY :)

XxYourBabyGirlxX2

8 0

3 years ago

Consider electromagnetic waves in free space. What is the wavelength of a wave that has the following frequencies? (a) 4.10 x 10

navik [9.2K]

Explanation:

To find the answer use the equation speed of light=wavelength multiplied by frequency (c=lambda*f) by substituting the value for the frequency the the speed of light

7 0

3 years ago