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nalin [4]
3 years ago
6

When energy is transformed or changed from one form into another, some of the energy will be lost to the environment as?

Physics
1 answer:
sasho [114]3 years ago
7 0
Generally it is lost as heat.
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PLEASE HELP FAST
love history [14]

a. Independent variable:   <em>TIME </em>

b. Dependent variable:   <em>DISTANCE</em>

4 0
3 years ago
Can someone please explain the quantum theory in simple terms
BaLLatris [955]
Quantum theory is the theoretical basis of modern physics that explains the nature and behavior of matter and energy on the atomic and subatomic level. The nature and behavior of matter and energy at that level is sometimes referred to as quantum physics and quantum mechanics.
6 0
3 years ago
9. A balloon is filled with 1000 cm3 of a gas weighing 1000 g. Will it rise or fall when it is released?
torisob [31]

We can calculate the density of the balloon as follows:

\rho=\frac{mass}{volume}=\frac{1000g}{1000cm^3}=\frac{1g}{cm^3}

Therefore, the balloon will fall

Since the density of air is about 0.00123 g/cm^3 , the balloon is much more dense than the surrounding air. As a result, the balloon weighs more than the air that it displaces so the balloon will fall.

3 0
1 year ago
Here is a graph of speed vs time. If the object is moving to the east, which BEST describes the speed and velocity of the graph?
Artemon [7]

Answer:

Both speed and velocity are changing.

Explanation:

They are both going up so both are changing

5 0
3 years ago
A force of 55N accelerates a 7.5kg wagon at 5.3 m/s^2 along a road. How large is the frictional force?
Varvara68 [4.7K]

Answer:

<h2>15.25 N</h2>

Explanation:

       A force of 55\text{ }N is acting on a wagon along the road. The wagon weights 7.5\text{ }kg. Acceleration of the wagon is given as 5.3\text{ }\frac{m}{s^{2}}.

       Consider the block as the system, the forces acting are Frictional force, Gravitational force, Normal reaction and External force applied by us.

       Gravitational Force and Normal Reaction cancel out each other.

       Net External Force = Mass of system/wagon \times Acceleration of wagon

       F_{ext}-F_{friction}=(7.5\text{ }kg)\times(5.3\text{ }\frac{m}{s^{2}})=39.75\text{ }N\\55\text{ }N-F_{friction}=39.75\text{ }N\\F_{friction}=15.25\text{ }N

F_{friction} has a negative sign because it opposes the motion of the wagon.

∴ Frictional Force = 15.25 N

4 0
3 years ago
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