Answer:
0.259 kJ/mol ≅ 0.26 kJ/mol.
Explanation:
- To solve this problem, we can use the relation:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat absorbed by ice (Q = ??? J).
m is the mass of the ice (m = 100.0 g).
c is the specific heat of water (c of ice = 4.186 J/g.°C).
ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 21.56°C - 25.0°C = -3.44°C).
<em>∵ Q = m.c.ΔT</em>
∴ Q = (100.0 g)(4.186 J/g.°C)(-3.44°C) = -1440 J = -1.44 kJ.
<em>∵ ΔH = Q/n</em>
n = mass/molar mass = (100.0 g)/(18.0 g/mol) = 5.556 mol.
∴ ΔH = (-1.44 kJ)/(5.556 mol) = 0.259 kJ/mol ≅ 0.26 kJ/mol.
Because the 4s orbital is at a lower energy level.
The 4s orbital has a lower energy because it is more <em>penetrating</em> than a 3d orbital. A 4s electron can get closer the nucleus than a 3d electron, so it has a lower potential energy.
The other options are incorrect because they contradict the correct one.
In the preparatory reaction that involves movement of pyruvic acid into mitochondria TAKES PLACE IN THE MITOCHONDRIAL MATRIX WHERE THE PYRUVIC ACID IS OXIDIZED AND CARBON DIOXIDE IS RELEASED. In this reaction, NAD+ is also reduced. The end products of a preparatory reaction are 4 NADH molecules, 4 hydrogen ions, 2 carbon dioxide molecules, 2 ATP molecules and 2 acetyl CoA molecules.
Answer:
b) maintains the pH of blood near 7.4.
c) regulates the blood pH at 7.4 +/- one pH unit.
f) is facilitated by the enzyme carbonic anhydrase, which interconverts carbon dioxide and water to carbonic acid (ionizes into bicarbonate and H^+).
Explanation:
The pH of human blood is slightly acidic i. e. 7.4. The enzyme carbonic anhydrase is responsible for the regulation to neutral and prevent it from acidic. the enzyme carbonic anhydrase helps in the conversion of carbon dioxide to carbonic acid and bicarbonate ions. When the blood reach to lungs, the bicarbonate ions convert back to CO2 and this carbondioxide is exhaled from the body.
