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Citrus2011 [14]
3 years ago
9

A red hot iron bar is dipped into 600 ml of water ( 600.g of water) which causes

Chemistry
1 answer:
Novosadov [1.4K]3 years ago
4 0

Answer:

168277.2 J

Explanation:

m = Mass of water = 600 g

c = Specific heat of water = 4.186 J/g°C

\Delta T = Change in temperature of water = 89-22=67^{\circ}\text{C}

We know that the amount of heat lost = amount of heat gained

Q=mc\Delta T\\\Rightarrow Q=600\times 4.186\times 67\\\Rightarrow Q=168277.2\ \text{J}

Heat lost by the iron bar is 168277.2 J.

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3 years ago
Twenty five grams of Iron 3 oxide react with an excess of carbon monoxide to form 15 g of Fe. Carbon dioxide is the other produc
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<h3>Answer:</h3>

Theoretical mass = 17.42 g

Percent yield of Fe = 86.11%

<h3>Explanation:</h3>

The equation for the reaction between iron (iii) oxide and carbon monoxide is given by;

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

We are required to calculate the theoretical yield and the percentage yield of Iron.

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Moles are given by dividing the mass of the compound by the molar mass.

Molar mass of Iron(iii) oxide = 159.69 g/mol

Moles of Iron(III) oxide = 25 g ÷ 159.69 g/mol

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Step 2: Moles of Iron produced

From the equation 1 mole of Iron(iii) oxide reacts to produce 2 moles of Fe.

Therefore, the mole ratio of Fe₂O₃ to Fe is 1 : 2.

Thus, moles of Fe = Moles of Fe₂O₃ × 2

                              = 0.156 moles × 2

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Step 3: Theoretical mass of iron produced

To calculate the mass of iron we multiply the number of moles of iron with the relative atomic mass.

Relative atomic mass = 55.845

Mass of iron = 0.312 moles × 55.845

                    = 17.42 g

Step 4: Percent yield of iron

% yield = (Actual mass ÷ Theoretical mass)×100

            = (15 g ÷ 17.42 g) × 100 %

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