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Citrus2011 [14]
3 years ago
9

A red hot iron bar is dipped into 600 ml of water ( 600.g of water) which causes

Chemistry
1 answer:
Novosadov [1.4K]3 years ago
4 0

Answer:

168277.2 J

Explanation:

m = Mass of water = 600 g

c = Specific heat of water = 4.186 J/g°C

\Delta T = Change in temperature of water = 89-22=67^{\circ}\text{C}

We know that the amount of heat lost = amount of heat gained

Q=mc\Delta T\\\Rightarrow Q=600\times 4.186\times 67\\\Rightarrow Q=168277.2\ \text{J}

Heat lost by the iron bar is 168277.2 J.

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In an experiment, 8.50 g of methane, CH4, was reacted with 15.9 g of oxygen gas to produce carbon dioxide and water. Determine t
exis [7]

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89.3 %

Explanation:

M(CH4) = 12+ 4*1 = 16 g/mol

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9.77 g * 1 mol/44 g = 0.2220 mol CO2

1)                                  CH4        + 2O2 -----> CO2 + 2H2O

from reaction             1 mol          2 mol

given                       0.5313 mol   (0.4969 mol)

1 mol CH4              --- 2 mol O2

0.5313 mol  CH4  --- x mol O2

x= 2*0.5313 = 1.0626 mol O2

We can see that for given amount of CH4 we do not have enough O2, so O2 is a limiting reactant.

2)                               CH4        + 2O2 -----> CO2 + 2H2O

from reaction                             2 mol        1 mol

given                                      0.4969 mol   x mol

x = 0.4969*1/2 = 0.2485 mol CO2 theoretical yield

3)

Practical yield CO2 = 0.2220 mol

Theoretical yield CO2 = 0.2485 mol

% yield = (0.2220/0.2485)*100% = 89.3 %

7 0
3 years ago
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