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2 years ago

Which is an example of nuclear energy being converted into heat and light energy?

Physics

2 answers:

likoan [24]2 years ago

6 0

The answer to the question is A

Akimi4 [234]2 years ago

3 0

Which is an example of nuclear energy being converted into heat and light energy?

a.the sun

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Using arrangement (a), how many rb atoms could be placed on a square surface that is 9.5 cm on a side? the diameter of a rubidiu

Leviafan [203]

Part a

Answer: $3.64\times10^{16}$

For the arrangement considered in part a, all the atoms are aligned side by side along the side of the square surface.

Along one side of the square, the number of atoms that could fit $=\frac {length\hspace{1mm}of\hspace{1mm}side}{diameter\hspace{1mm}of\hspace{1mm}atom}=\frac{9.5\times10^{-2}m}{4.95\times10^{-10}m}=1.91\times10^8 atoms$

This is along one side. On the entire surface:

Number of atoms $= (1.91\times10^8 )^2=3.64\times10^{16} atoms$

Part b

Answer: $4.23\times10^{16}$

consider the attached figure below:

The next layer of atoms are filled in the depressions of the first layer. The vertical distance between the two atoms would change. Consider an equilateral triangle drawn by joining the centers of the three atoms.

The atoms along the horizontal side would be aligned side by side; same as above $=1.91\times10^8 atoms$

The number of atoms along vertical side would vary. vertical distance between two atoms can be calculate using equilateral triangle as shown below.

an equilateral triangle has all the angles $= 60^o$

Let the vertical distance be y.

Then, $y = 2r sin60^o$

where r is the radius of each atom. $2r= 4.95\times10^{-10} m$

$y=4.95\times10^{-10} m\times sin60^o=4.28\times10^{-10} m$

The number of atoms along the vertical side $= \frac{9.5\times10^{-2}m}{4.28\times10^{-10}m}=2.21\times10^8 atoms$

Total number of atoms in this kind of arrangement $= 1.91\times10^8\times2.21\times10^8=4.23\times10^{16} atoms$

6 0

2 years ago

What type of path does a moving object follow in the absence of a force?.

Amanda [17]

Answer:

When there is no force acting on a body then a moving object move in a straight line with constant velocity and an object in rest stays in rest.

Explanation:

When there is no force acting on a body then a moving object move in a straight line with constant velocity and an object in rest stays in rest.

3 0

2 years ago

Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.5 mm in diameter, to 30.0 m of copper wire 1.6 mm in diameter

alukav5142 [94]

Answer: 0.258

Explanation:

The resistance $R$ of a wire is calculated by the following formula:

$R=\rho\frac{l}{s}$ (1)

Where:

$\rho$ is the resistivity of the material the wire is made of. For aluminium is $\rho_{Al}=2.65(10)^{-8}m\Omega$ and for copper is $\rho_{Cu}=1.68(10)^{-8}m\Omega$

$l$ is the length of the wire, which in the case of aluminium is $l_{Al}=12m$ , and in the case of copper is $l_{Cu}=30m$

$s$ is the transversal area of the wire. In this case is a circumference for both wires, so we will use the formula of the area of the circumference:

$s=\pi{(\frac{d}{2})}^{2}$ (2) Where $d$ is the diameter of the circumference.

For aluminium wire the diameter is $d_{Al}=2.5mm=0.0025m$ and for copper is $d_{Cu}=1.6mm=0.0016m$

So, in this problem we have two transversal areas:

For aluminium:

$s_{Al}=\pi{(\frac{d_{AL}}{2})}^{2}=\pi{(\frac{0.0025m}{2})}^{2}$

$s_{Al}=0.000004908m^{2}$ (3)

For copper:

$s_{Cu}=\pi{\frac{(d_{Cu}}{2})}^{2}=\pi{(\frac{0.0016m}{2})}^{2}$

$s_{Cu}=0.00000201m^{2}$ (4)

Now we have to calculate the resistance for each wire:

Aluminium wire:

$R_{Al}=2.65(10)^{-8}m\Omega\frac{12m}{0.000004908m^{2}}$ (5)

$R_{Al}=0.0647\Omega$ (6) Resistance of aluminium wire

Copper wire:

$R_{Cu}=1.68(10)^{-8}m\Omega\frac{30m}{0.00000201m^{2}}$ (6)

$R_{Cu}=0.250\Omega$ (7) Resistance of copper wire

At this point we are able to calculate the ratio of the resistance of both wires:

$Ratio=\frac{R_{Al}}{R_{Cu}}$ (8)

$\frac{R_{Al}}{R_{Cu}}=\frac{0.0647\Omega}{0.250\Omega}$ (9)

Finally:

$\frac{R_{Al}}{R_{Cu}}=0.258$ This is the ratio

3 0

3 years ago

Cognitive psychology deals with ____.

Elanso [62]

Answer:

Explanation:

Because the main focus of cognitive psychology is on the metal processes that affect behavior

3 0

1 year ago

In order to walk barefoot on hot coals without hurting your feet

siniylev [52]

Before a person walks through burning coal, the person will make sure their feet are very wet. When they start walking on the coal, this moisture will evaporate and form a protective gas layer underneath the person's feet. You can see examples of this if you happen to drip some water on a hot stove or any very hot surface. The water will very easily glide around on top of a newly formed layer of air underneath it -- like air hockey pucks on an air hockey table. Note that when someone walks through burning coal, typically this is also done very quickly to prevent a great deal of exposure to possible harm. By walking quickly, thinking positively, and letting the water cushion you from immediate danger over a short distance, such a task is possible. You may have also heard of physics teachers demonstrating how this principle works by sticking their hand first in a bucket of water and then quickly in a bucket of boiling molten lead. In the lead, their hand is protected briefly by a layer of gas from the evaporated water (the water vapor). I'm fairly sure that there is a name for this particular layer of gas, but I'm afraid the name is beyond me at the moment. In other words, water vapor has a low heat capacity and poor thermal conduction. Very often, the coals or wood embers that are used in fire walking also have a low heat capacity. Sweat produced on the bottom of people's feet also helps form a protective water vapor. All of this together makes it possible, if moving quickly enough, to walk across hot coals without getting burned. WARNING: Do not attempt to perform any of the actions described above. You can seriously injure yourself. Answered by: Ted Pavlic, Electrical Engineering Undergrad Student, Ohio St. (citing my source)

5 0

3 years ago