All categories

3 years ago

Anyone know how this work ?? If u know help me it is an exam

Physics

1 answer:

myrzilka [38]3 years ago

6 0

Answer:

D) This is the correct answer

Explanation:

In this exercise the two ball loads are suspended by a thread.

To answer this exercise, let us remember that charges of the same sign repel and charges of a different sign attract.

Therefore, for the system to maintain equilibrium, the two charges must be of the same sign.

When examining the different proposals

A) in this case, as a sphere has no charge, there is no electric force and the induced charge is of the opposite sign, so the spheres attract each other

B) in this case there is an electric force, but being of a different sign, the force is attractive so the system is not in equilibrium

C) as the charges are of different magnitude the system does not have equal angles

D) This is the correct answer, since the charges have the same magnitude and are of the same sign, so the force is repulsive and is counteracted by the weight component

F_e = W sin θ

You might be interested in

Plz help me asap !!!!!!!!!!

nlexa [21]

Answer:

B- 65km

C- 2.8km/h

D- average speed

6 0

3 years ago

The flower of the species Rosa verdus can be either green or red. in the species a single gene with two alleles determines flowe

Simora [160]

Since G is a dominate trait the 2 genotypes would be Gg or GG

4 0

4 years ago

Read 2 more answers

A 3.0-kg object moves to the right with a speed of 2.0 m/s. It collides in a perfectly elastic collision with a 6.0-kg object mo

Zinaida [17]

Answer:

The kinetic energy of the system after the collision is 9 J.

Explanation:

It is given that,

Mass of object 1, m₁ = 3 kg

Speed of object 1, v₁ = 2 m/s

Mass of object 2, m₂ = 6 kg

Speed of object 2, v₂ = -1 m/s (it is moving in left)

Since, the collision is elastic. The kinetic energy of the system before the collision is equal to the kinetic energy of the system after the collision. Let it is E. So,

$E=\dfrac{1}{2}m_1v_1^2+\dfrac{1}{2}m_2v_1^2$

$E=\dfrac{1}{2}\times 3\ kg\times (2\ m/s)^2+\dfrac{1}{2}\times 6\ kg\times (-1\ m/s)^2$

E = 9 J

So, the kinetic energy of the system after the collision is 9 J. Hence, this is the required solution.

3 0

3 years ago

All waves must ____ have to travel through

babunello [35]

<h2>All waves must ____ have to travel through </h2>

Explanation:

Wave

It is the periodic disturbance in a medium.

Types of Wave

There are two types of wave in general depending upon their propagation through a substance.

• Mechanical

• Electromagnetic

Mechanical Wave

It is the kind of wave which needs medium to travel. For example: Sound Wave

That means sound can be heard only whenever there is presence of certain substance like water, glass, air etc .It can’t be heard in vacuum no matter how loud is the sound.

Electromagnetic Wave

Is that which can travel through medium as well as through vacuum. For example: Light

But unlike sound, light can be seen through a substance or in vacuum. That is the reason it is referred as electromagnetic wave.

6 0

3 years ago

A distant galaxy is determined to be 150 million light years distant and moving away from us; using the Hubble law determine its

dlinn [17]

Your question kind of petered out there towards the end and you didn't specify
the terms, so I'll pick my own.

The "Hubble Constant" hasn't yet been pinned down precisely, so let's pick a
round number that's in the neighborhood of the last 20 years of measurements:

   <em>70 km per second per megaparsec</em>.

We'll also need to know that 1 parsec = about 3.262 light years.

So the speed of your receding galaxy is

   (Distance in LY) x (1 megaparsec / 3,262,000 LY) x (70 km/sec-mpsc) =

      (150 million) x (1 / 3,262,000) x (70 km/sec) =

   <em>3,219 km/sec </em>in the direction away from us (rounded)

4 0

3 years ago