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Nat2105 [25]
3 years ago
8

Calculate the total resistance for a 650ohm , a 350 ohm , and a 1000 ohm resistor connected in series

Physics
2 answers:
Mekhanik [1.2K]3 years ago
5 0

Answer:

2000 ohms

Explanation:

Resisters in series just add.

Rt = R1 + R2 + R3

R1 = 650 ohm

R2 = 350 ohm

R3 = 1000 ohm

Rt = 650 + 350 + 1000

Rt = 2000 ohms.

VikaD [51]3 years ago
4 0

The total effective resistance of several resistors in SERIES is just the sum of all the individual resistances.  

So the effective resistance of 650Ω,  350Ω,  and  1,000Ω  in series is

Sum = (650Ω + 350Ω + 1,000Ω)

<em>Sum = 2,000 ohms</em>

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densk [106]
<span>through friction between her feet and the carpet </span>
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4 years ago
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A liquid with a density of 900kg/m 3 is stored in a pressurized, closed storage tank. The tank is cylindrical with a 10m diamete
Orlov [11]

Answer:

18.62 m/s

Explanation:

Given that:

A liquid with a density of 900 kg/m 3 is stored in a pressurized, closed storage tank.

Diameter of the tank = 10 m

The absolute pressure in the tank above the liquid is 200 kPa = 200, 000 Pa

At pressure of 200 kPa   ; the final velocity = 0

Atmospheric pressure at 5cm = 101325 Pa

We are to calculate the initial velocity of a fluid jet when a 5cm diameter orifice is opened at point A?

By using Bernoulli's theorem between the shaded portion in the diagram;

we have:

Pa \ + \ \frac{1}{2} \  \delta \ v^2_1 \ + \ \delta gy_1 = P + \delta gy_2

\frac{1}{2} \  \delta \ v^2_1 \ = P + \delta gy_2 -  \ \delta gy_1  - Pa

\frac{1}{2} \  \delta \ v^2_1 \ =  \delta g(y_2 -y_1 )+   ( P   - Pa )

v_1 \ =  \sqrt{ \frac {2 \ \delta g(y_2 -y_1 )+  2  ( P   - Pa )}{\delta}}

where;

Pa = atmospheric pressure = 101325 Pa

\delta = density of liquid = 900 kg/m³

v_1 = initial velocity = ???

g = 9.8 m/s²

y_1 = height of the hole from the buttom

y_2 = height of the liquid surface from the button

v_1 \ =  \sqrt{ \frac {2*900*9.8(7 -  0.5 )+  2  ( 200,000   - 101325 )}{900}}

v_1 = 18.62 \ m/s

Thus, the initial  velocity of the fluid jet  = 18.62 m/s

3 0
3 years ago
Eight books, each 4.6 cm thick and of mass 1.8 kg, lie on a flat table. How much work work is required to stack them on top of o
pantera1 [17]

Answer:

529.92Newton Meters

Explanation:

Work=force x displacement

8books in total

force is 1.8kg

dispplacement is 4.6cm

times both units by 8 and u get

force - 14,4

displacement - 36.8

now times boht together and u get 529.92nm

3 0
2 years ago
que tiempo tarda juan en su carro al llegar al trabajo si lleva una velocidad de 25 m/s a una distancia de 5m
kramer

Answer:

0.2s

Explanation:

Given parameters:

Speed  = 25m/s

Distance  = 5m

Unknown:

Time taken for Juan to get to his work  = ?

Solution:

To solve this problem we use the relationship below:

 

   Speed  = \frac{distance}{time}  

  Time  =  \frac{distance }{speed}  

So;

   Time  = \frac{5}{25}   = 0.2s

4 0
3 years ago
A 87 kgkg skydiver can be modeled as a rectangular "box" with dimensions 18 cmcm ×× 47 cmcm ×× 180 cmcm . If he falls feet first
garik1379 [7]

Answer:

Therefore the terminal velocity = 1.45 m/s

Explanation:

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V_t= terminal velocity

w = weight of the object = mg

c_d = drag coefficient=0.80

A= frontal area

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m = mass = 8 kg

g= acceleration due to gravity = 9.8 m/s²

Front area = length× breadth

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Therefore the terminal velocity

v_t= \sqrt{\frac{2\times 87\times 9.8}{0.80\times 846 \times 1.2}

    =1.45 m/s

Therefore the terminal velocity = 1.45 m/s

8 0
3 years ago
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