Y = 2x - 5
3x + 8y + 32 = 56
3x + 8(2x - 5) + 32 = 56
3x + 8(2x) - 8(5) + 32 = 56
3x + 16x - 40 + 32 = 56
19x - 8 = 56
<u> + 8 + 8</u>
<u>19x</u> = <u>64</u>
19 19
x = 3.4
y = 2(3.4) - 5
y = 6.8 - 5
y = 1.8
(x, y) = (3.4, 1.8)
Answer:
nice
Step-by-step explanation:
Answer:
is one to one mapping, it is not onto mapping
Step-by-step explanation:
f₁(x) is one to one mapping
Let 
f₁(x) = f₁(y):
x₁³ = y₁³
f₁(x) is not onto mapping
Example: If f₁(x) = 7,
x₁³ = 7
![x_{1} = \sqrt[3]{7}](https://tex.z-dn.net/?f=x_%7B1%7D%20%3D%20%5Csqrt%5B3%5D%7B7%7D)
x₁ is not an element of Z
is one to one mapping, it is not onto mapping
Answer:
K = 43
Step-by-step explanation:
We'll begin by determining the gradient of the equation 5y + 4x = 8. This can be obtained as follow:
5y + 4x = 8
Rearrange
5y = 8 – 4x
5y = –4x + 8
Comparing 5y = –4x + 8 with y = mx + c, the gradient m is –4
Next, we shall determine the gradient of the line perpendicular to the line with equation 5y = 8 – 4x.
This can be obtained as follow:
For perpendicular lines, their gradient is given by:
m1 × m2 = – 1
With the above formula, we can obtain the gradient of the line as follow:
m1 × m2 = – 1
m1 = –4
–4 × m2 = – 1
Divide both side by –4
m2 = –1/–4
m2 = 1/4
Finally, we shall determine the value of k as follow:
Coordinate => (k, 4) and (3, –6)
x1 coordinate = k
y1 coordinate = 4
x2 coordinate = 3
y2 coordinate = –6
Gradient (m) = 1/4
m = (y2 – y1) / (x2 – x1)
1/4 = (–6 – 4) / (3 – K)
1/4 = –10 /(3 – K)
Cross multiply
3 – K = 4 × –10
3 – K = –40
Collect like terms
– K = – 40 –3
–k = –43
Divide both side by – 1
K = –43/–1
k = 43
First set it up like this:
<span>then add a zero on to the 18 and a decimal point like this: </span>
then solve for 180/32 and add a decimal in the same location that it is in the 18.0 Hope this helps!
