The correct choice is :
The final momentum of the bullet/block is equal to the initial momentum of the bullet.
initially the block was at rest , hence
initial momentum of the block = 0
so total initial momentum was simply equal to initial momentum of bullet only.
after collision , the bullet gets embedded in the block , and hence both block-bullet move together at common velocity . according to conservation of momentum , momentum remains conserved in any type of collision.
so final momentum of bullet-block system = initial momentum of bullet
For this problem, we use the Coulomb's law written in equation as:
F = kQ₁Q₂/d²
where
F is the electrical force
k is a constant equal to 9×10⁹
Q₁ and Q₂ are the charge of the two objects
d is the distance between the two objects
Substituting the values:
F = (9×10⁹)(-22×10⁻⁹ C)(-22×10⁻⁹ C)/(0.10 m)²
F = 0.0004356 N
0.12244898 is the value obtained when solving the given.
<u>Explanation:</u>
Given:
3 times 10 to the 8th power can be expressed in equation format as (3 times symbolizes ‘multiplication’ then it is to the tenth power of 8)
2.45 times 10 to the 9th power can be expressed in equation format as (2.45 times symbolizes ‘multiplication’, then it is to the tenth power of 9)
Asked to find the solution when dividing the above,
When the tenth power of any value goes from denominator to numerator and vice-versa, presents in opposite sign to that it possess (like when ‘ ' goes to numerator changed as ' ').
Now by solving the above equation, we get
Because the idea that the ground that we live, stand, and build on is actually moving beneath us blew the minds of scientists.
Answer:
The value of 60.2 mg in to g is 0.0602.
Explanation:
We need to calculate the 60.2 mg in to gram.
Conversion mg to g :
1 g = 1000 mg
Using this conversion,
So,
Hence, The value of 60.2 mg in to g is 0.0602.