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masha68 [24]
3 years ago
6

A 7.3 cm diameter loop of wire is initially oriented so that its plane is perpendicular to a magnetic field of 0.61 T pointing u

p. During the course of 0.13 s the field is changed to one of 0.28 T pointing down. What is the magnitude of the induced emf in the coil in mV?
Physics
1 answer:
kenny6666 [7]3 years ago
3 0

Answer:

induced emf =  28.65 mV

Explanation:

given data

diameter = 7.3 cm

magnetic field = 0.61

time period = 0.13 s

to find out

magnitude of the induced emf

solution

we know radius is diameter / 2

radius = 7.3 / 2

radius = 3.65 m

so induced emf is dπ/dt  = Adb/dt

induced emf =  A × ΔB / Δt

induced emf =  πr² × ΔB / Δt

induced emf =  π (0..65)² × ( 0.61 - (-0.28))  / 0.13

induced emf =  0.0286538 V

so induced emf =  28.65 mV

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finlep [7]

Answer:

Rachel(2.5,0)

ball(6.5,4.7)

b.R=10.15m/s, 27.57deg

Explanation:

The reference angle of Rachel is 00^{0} while the ball is at 36^{0}

resolving rachel's speed to the horizontal, we have

Ux=2.5cos0

Ux=2.5m/s

resolving rachel's speed to the vertical we have,

Uy=2.5sin0

Uy=0

for the ball

resolving the speed to its horizontal component

Ux=8cos36

Ux=6.5m/s

Uy=8sin36

Uy=4.7m/s

Rachel(2.5,0)

ball(6.5,4.7)

To get the resultant of their speed

Add the horizontal speed of rachel to that of the ball to get the total horizontal speed

Add the vertical speed of rachel and the ball to get the total vertical speed component

TUx=2.5+6.5=9M/S

TUy=0+4.7=4.7m/s

R=\sqrt{(TUx^2+TUy^2}

R=\sqrt{(9^2+4.7^2}

R=\sqrt{(103)}

R=10.15m/s

the direction

tan\alpha=TUy/TUx

tan\alpha=4.7/9

\alpha=tan^-1(0.522)

\alpha=27.57deg

4 0
3 years ago
9. How is spring potential energy determined from a force versus position graph?
kolezko [41]

Answer: The potential energy associated with a mass attached to a spring depends on how much the spring is stretched or compressed. ... The gravitational force on the mass is −mg (“−” because the force points down). The force is the negative of the slope on the potential energy versus position graph.

Explanation:

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8 0
3 years ago
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suter [353]

Answer:

Explanation:

The first diagram (by the left) is an endothermic reaction. In this reaction, the products are higher in energy than the reactants. Heat/Energy is absorbed in this reaction and enthalpy is positive. In second diagram (by the right) is an exothermic reaction. In this reaction, the reactants are higher in energy than the products. In this reaction, heat/energy is released.

7 0
3 years ago
Each plate of a parallel‑plate capacitor is a square of side 3.63 cm, and the plates are separated by 0.473 mm. The capacitor is
NARA [144]

Answer:

E= 55.53 x 10³ V/m

Explanation:

Given that

a=  3.63 cm

Area ,A= a²

distance ,d= 0.473 mm

Stored energy ,U = 8.49 nJ

Value of capacitor given as

C=\dfrac{\varepsilon _oA}{d}

By putting the values

C=\dfrac{8.85\times 10^{-12}\times 3.63^2\times 10^{-4}}{0.473\times 10^{-3}}

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U=\dfrac{1}{2}CV^2

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V=\sqrt{\dfrac{2U}{C}}

V=\sqrt{\dfrac{2\times 8.49\times 10^{-9}}{2.46\times 10^{-11}}}

V=26.27 V

V= E d

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26.27 = E x 0.473 x 10⁻³

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7 0
4 years ago
True or false: a probability contour represents a bounded, finite volume about a nucleus in which there is a substantial probabi
erastovalidia [21]

A probability contour represents a bounded, finite volume about a nucleus in which there is a substantial probability of finding the electron is TRUE.

The rectangular of the wave characteristic, ψ2 , represents the opportunity of locating an electron in a given vicinity within the atom. probability finding electron at nucleus is zero.

An orbital is a mathematical feature that has a fee at all points in space. The magnitude squared of that fee is the chance according to volume of locating an electron in that volume of area.

The probability of locating electron in nodes is 0, but there are electron densities on all round nodes. The node is a point or a floor (relying at the type of node) so the volume of the vicinity wherein ψ=zero is zero. we want to position V=zero and we get P=zero so the chance of finding the electron on the node is zero.

Learn more about electron here:-brainly.com/question/860094

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7 0
2 years ago
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