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serg [7]
2 years ago
10

What’s 3 times 10 to the 8th power divided by 2.45 times 10 to the 9th power

Physics
1 answer:
Virty [35]2 years ago
5 0

0.12244898 is the value obtained when solving the given.

<u>Explanation:</u>

Given:

3 times 10 to the 8th power can be expressed in equation format as 3 \times 10^{8} (3 times symbolizes ‘multiplication’ then it is to the tenth power of 8)

2.45 times 10 to the 9th power can be expressed in equation format as 2.45 \times 10^{9} (2.45 times symbolizes ‘multiplication’, then it is to the tenth power of 9)

Asked to find the solution when dividing the above,

                 \frac{3 \times 10^{8}}{2.45 \times 10^{9}}=\frac{3}{2.45} \times 10^{8-9}

When the tenth power of any value goes from denominator to numerator and vice-versa, presents in opposite sign to that it possess (like when ‘10^{9} ' goes to numerator changed as ' 10^{-9} ').

Now by solving the above equation, we get

                \frac{3}{2.45} \times 10^{8-9}=1.22 \times 10^{-1}=\frac{1.22}{10}=0.12244898

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Answer:

Technician A is right.                                                    

Explanation:

Given that,

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Explanation:

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Conserving Energy i.e.

0.9(Rotational Energy of Flywheel)= change in Kinetic Energy of bus

Let \omegabe the angular velocity of Flywheel

0.9\cdot \frac{I\omega ^2}{2}=\frac{m_bv^2}{2}

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Answer:

c. vf is greator than v2, but less than v1

Explanation:

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In a system of colliding bodies the total momentum of the system just before the collision is the same as the total momentum just after the collision.  

Collisions in which the kinetic energy is conserved are called elastic collision.

Collisions in which the kinetic energy is not conserved are called inelastic collisions.  If the two objects stick together after the collision and move with a common velocity, the collision is said to be perfectly inelastic.

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Therefore,

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c. vf is greater than v2, but less than v1 is correct.

d. vf = v1 is wrong because vf is less than v1

4 0
3 years ago
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