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MakcuM [25]
3 years ago
8

Which of the following is the volume of the shaded in Of the sphere?

Physics
1 answer:
marysya [2.9K]3 years ago
7 0

Answer:

The correct option is;

πR³(2/3 + (1/3)cos³θ - cosθ)

Explanation:

The volume of a segment of a sphere is given by the relation;

V = \pi \cdot h^2 \cdot \left (R - \dfrac{h}{3} \right)

We note that h = R - R·cos(θ)

Therefore by substituting the value of h in the equation of a segment of a sphere, we have;

V = \pi \cdot \left (R - R\cdot cos(\theta) \right ) ^2 \cdot \left (R - \dfrac{\left (R - R\cdot cos(\theta) \right )}{3} \right)

Which gives;

\dfrac{R^3\cdot \pi \cdot cos^3 (\theta) -3 \cdot R^3 \cdot\pi \cdot cos (\theta) +  2 \cdot R^3 \cdot \pi}{3}

R^3\cdot \pi \cdot  \left (\dfrac{cos^3 (\theta) -3 \cdot cos (\theta) +  2 }{3} \right )

R^3\cdot \pi \cdot  \left (\dfrac{cos^3 (\theta) +  2 }{3} -  cos (\theta)  \right )

R^3\cdot \pi \cdot  \left (\dfrac{cos^3 (\theta) }{3} + \dfrac{2}{3} -  cos (\theta)  \right )

Therefore, the correct option is πR³(2/3 + (1/3)cos³θ - cosθ).

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Answer:

This type of star is called the "white dwarf." When a very massive star exhausts its nuclear fuel it explodes as a supernova.

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What is the value of x in the equation<br> 1 x - 2 = 1899<br> 56<br> 52<br> 52<br> 56
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A 4,350 kg truck traveling east has a momentum of 26,100kg m/s what's the trucks velocity
Angelina_Jolie [31]

Answer:

6 m/s East

Explanation:

Momentum = Mass . Velocity

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4 0
3 years ago
C. You push a sled of mass 15 kg across the snow with a force of 180 N for a distance of 2.5 m. There is no friction. If the sle
Svetllana [295]

Explanation:

7.7 m/s

1st determine you subject slade to you have a mass of 15 kg being subjected to a force of 180N

so.

180N/15kg=180(kg m)/s^2/15kg=12 ms^2

now determine how long u pushed it

d=0.5 A T^2

sutable the known values getting

2.5 m = 0.5 12 ms^2 T^2

2.5m= 0.6 ms^2 T^2

0.41667 s^2=T^2

0.645497224s=T

the velocity multiply the time by the acceleration giving

0.645497224 s 12 ms^2 =7.745966692 ms.

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4 0
3 years ago
A stick of mass m and length / is pivoted at one
AfilCa [17]

Answer:

  • Potential Energy = mgl (1 - cosθ)

Explanation:

<h3>Given :-</h3>
  • Mass of stick = m
  • Length of stick = l
  • Angle = θ

<h3>To Find :-</h3>
  • Increase potential energy

<h3>Solution :-</h3>

✪ <u>According to the given </u><u>data</u> :-

 ⠀⠀⠀→ cosθ = ᵇ/ₕ

 ⠀⠀⠀→ cosθ = ᴬᴮ/l

 ⠀⠀⠀→ AB = l cosθ

❂ <u>For </u><u>Height</u> :-

 ⠀⠀⠀→ h = l - l cosθ

 ⠀⠀⠀→ h = l (1-cosθ)

☯ <u>As we know that</u>

 ⠀⠀⠀→ Potential Energy = mgh

 ⠀⠀⠀→ Potential Energy = mg × l (1-cosθ)

 ⠀⠀⠀→ Potential Energy = mgl (1-cosθ)

5 0
3 years ago
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