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Jlenok [28]
3 years ago
13

Someone please help me

Physics
1 answer:
SIZIF [17.4K]3 years ago
7 0
The answer for this question is A. The layers are orignally horizontal 
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Aliun [14]

Answer:

ppap

Explanation:

idk man :vvvv. v vv.

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Valley-river Landslide-Gravity Frost wedging- Glacier Canyon-Ice.

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I think that's right

4 0
3 years ago
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Nonamiya [84]
It’s the velocity to the trex then divided by pie to get 8.3
6 0
2 years ago
An oak block had the following dimension, 2 cm by 2 cm and 5 cm in height. A copper block had the same dimensions. The copper bl
antiseptic1488 [7]

Answer:

ρ_body = 1000 kg / m³

Explanation:

This is an exercise in fluid mechanics, specifically we must use the Archimedean principle, which states that the thrust is equal to the weight of the dislodged liquid.

In this case let's start by finding the volume of our body

oak block

      v = l to h

       v = 0.02 0.02 0.05

       V = 2 10⁻⁵ m³

cooper block indicate that it has the same dimensions so its volume is the same, the total volume of the body is

        V_total = 4 10⁻⁵ m³

as they indicate that the body is fully submerged there is a balance between weight and thrust

          B - W = 0

the push is

          B = ρ_fluid g V_total

the body weight is

         ρ_body = M / V_total

          M = ρ_body V_total

         W = Mg

          W = ρ_body V_total g

we substitute

          ρ_fluid g V_total = ρ_body V_total g

        ρ_body = ρ_fluid

in this case the body is in equilibrium in the fluid, in case the density of the body is greater than that of the fluid, the body sinks

Therefore the average density is equal to the density of the fluid, since since it is water the density is

              ρ_body = 1000 kg / m³

8 0
3 years ago
John and mary are skating at an ice rink. john skates at a constant speed of 6.7 m/s, with respect to the ice surface, directly
iragen [17]
60.3° from due south and 5.89 m/s    For this problem, first calculate a translation that will put John's destination directly on the origin and apply that translation to Mary's destination. Then the vector from the origin to Mary's new destination will be the relative vector of Mary as compared to John. So John is traveling due south at 6.7 m/s. After 1 second, he will be at coordinates (0,-6.7). The translation will be (0,6.7)  Mary is traveling 28° West of due south. So her location after 1 second will be  (-sin(28)*10.9, -cos(28)*10.9) = (-5.117240034, -9.624128762)  After translating that coordinate up by 6.7, you get  (-5.117240034, -2.924128762)  The tangent of the angle will be 2.924128762/5.117240034 = 0.57142693  The arc tangent is atan(0.57142693) = 29.74481039° Subtract that value from 90 since you want the complement of the angle which is now 60.25518961°    So Mary is traveling 60.3° relative to due south as seen from John's point of view.  The magnitude of her relative speed is  sqrt(-5.117240034^2 + -2.924128762^2) = 5.893783 m/s    Rounding the results to 3 significant digits results in 60.3° and 5.89 m/s
8 0
3 years ago
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