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salantis [7]
3 years ago
8

The major contributions of Maury included:

Physics
1 answer:
scoray [572]3 years ago
6 0
The best and most correct answer among the choices provided by your question is the second choice.

<span>The major contributions of Maury included mapping the ocean bottom.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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When a certain isotope, such as U-238, is hit by a neutron, it will always split into the same smaller nuclei.
nadezda [96]

Answer: falss

Explanation:

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3 years ago
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If the focal length of a concave mirror is 18cm, find its radius of curvature.
Galina-37 [17]

Given :

The focal length of a concave mirror is 18 cm.

To Find :

The radius of curvature of the concave mirror.

Solution :

We know,

\text{Focal length}=\dfrac{\text{Radius of curvature}}{2}\\\\F=\dfrac{R}{2}\\\\R = 18\times 2\ cm\\\\R = 36 \ cm

Therefore, the radius of curvature of concave mirror is 36 cm.

Hence, this is the required solution.

8 0
3 years ago
HELP ASAP WITH number 6 plz
Alika [10]
The answer would be c
6 0
3 years ago
The current supplied by a battery as a function of time is I(t) = (0.88 A) e^(-t*6 hr). What is the total number of electrons tr
Degger [83]

Answer:

e. 1.2 x 10²³

Explanation:

According to the problem, The current equation is given by:

I(t)=0.88e^{-t/6\times3600s}

Here time is in seconds.

Consider at t=0 s the current starts to flow due to battery and the current stops when the time t tends to infinite.

The relation between current and number of charge carriers is:

q=\int\limits {I} \, dt

Here the limits of integration is from 0 to infinite. So,

q=\int\limits {0.88e^{-t/6\times3600s}}\, dt

q=0.88\times(-6\times3600)(0-1)

q = 1.90 x 10⁴ C

Consider N be the total number of charge carriers. So,

q = N e

Here e is electronic charge and its value is 1.69 x 10⁻¹⁹ C.

N = q/e

Substitute the suitable values in the above equation.

N= \frac{1.9\times10^{4} }{1.69\times10^{-19}}

N = 1.2 x 10²³

8 0
3 years ago
What happens to the density if the volume of an object decrease and the mass remains the same?
vekshin1
The density would increase because you still have the same amount of weight, but it is just packed more tightly in a smaller object.
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