Answer:
d
Explanation:
lol Hope's this helps lovely
The mass of the Book is 2.27 kg.
B. An ear squeeze occurs when the pressure inside the middle ear space is less than ambient (surrounding) pressure.
<h3>When external ear squeeze occurs</h3>
External ear squeeze occurs when gas trapped in the external ear canal remains at atmospheric pressure while the external water pressure increases during descent.
Thus, we can conclude that, an ear squeeze occurs when the pressure inside the middle ear space is less than ambient (surrounding) pressure.
Learn more about ear squeeze here: brainly.com/question/11430998
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Answer:

Explanation:
The amount of heat released from water is equal to the sum of latent and sensible heats. Let suppose that water is initially at a temperature of
. Then:


Finally, the amount of heat released from water is now computed by replacing variables:
![\Delta H_{tot} = (1\,mol)\cdot \left[\left(75.3\,\frac{kJ}{mol\cdot K} \right)\cdot (25^{\circ}C-0^{\circ}C)+ 6.025\,\frac{kJ}{mol} + \left(37.7\,\frac{kJ}{mol\cdot K} \right)\cdot (0 + 10^{\circ}C)\right]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Btot%7D%20%3D%20%281%5C%2Cmol%29%5Ccdot%20%5Cleft%5B%5Cleft%2875.3%5C%2C%5Cfrac%7BkJ%7D%7Bmol%5Ccdot%20K%7D%20%5Cright%29%5Ccdot%20%2825%5E%7B%5Ccirc%7DC-0%5E%7B%5Ccirc%7DC%29%2B%206.025%5C%2C%5Cfrac%7BkJ%7D%7Bmol%7D%20%2B%20%5Cleft%2837.7%5C%2C%5Cfrac%7BkJ%7D%7Bmol%5Ccdot%20K%7D%20%5Cright%29%5Ccdot%20%280%20%2B%2010%5E%7B%5Ccirc%7DC%29%5Cright%5D)

Answer:
a) F = 21.16 N, b) a = 3.17 10²⁸ m / s
Explanation:
a) The outside between the alpha particles is the electric force, given by Coulomb's law
F =
in that case the two charges are of equal magnitude
q₁ = q₂ = 2q
let's calculate
F =
F = 21.16 N
this force is repulsive because the charges are of the same sign
b) what is the initial acceleration
F = ma
a = F / m
a =
21.16 / 4.0025 1.67 10-27
a = 3.17 10²⁸ m / s
this acceleration is in the direction of moving away the alpha particles