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Sauron [17]
3 years ago
11

Alanna spots a bird in her back yard. The bird is sitting on a tree. Explain how the outer coverings of the bird and tree are di

fferent and have different functions.
Physics
1 answer:
eduard3 years ago
6 0

Answer:

the outer covering of a bird is usually for camoflauge (idk how to spell) or to attract mates and the outer part of a tree is used for protection i think, correct me if im wrong ;-;

Explanation:

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If the force vector has a magnitude of F = 12.5 N, the displacement has a length of Δr = 0.75 m, and the angle between the vecto
Thepotemich [5.8K]

Answer: 8.81 J

Explanation: The scalar or dot product of 2 vector equals the product of the magnitude of both vectors and the cosine value of the angle between them

Magnitude of vector f (force) as given in the question = 12.5N

Magnitude of length = 0.75m

Angle between vectors = 25°

F. Δr = 12.5 * 0.75 * cos 25

F. Δr = 12.5 * 0.75 * 0.9063

F. Δr = 8.81 J

7 0
3 years ago
The Andromeda Galaxy is faintly visible to the naked eye in the constellation Andromeda. Suppose instead it were located in the
Kaylis [27]

Answer:

a) We could not see it at all.

Explanation:

The most distant object that can be seen is the andromeda galaxy, which we may have a slight view of. The andromeda galaxy is a large galaxy that along with the previous two is also part of the local group. Spiral-type galaxy that is approximately 250,000 light years in diameter (more than twice the diameter of the Milky Way!) And is about 2.9 million light years away from our galaxy. Because of its distance, we have difficulty visualizing this galaxy, we would have this difficulty even if the andromeda galaxy was in the center of the Milky Way, but maintaining its current distance. That is, even if the andromeda galaxy were located in the same direction in space as the center of the Milky Way (but still at its current distance), we could not see it at all.

8 0
3 years ago
What would happen to the wavelength if the frequency was doubled?
ira [324]

Answer:

λ = hv

If frequency is doubled :

λ = h × 2v

λ = 2hv

Thus wavelength is doubled

7 0
3 years ago
The velocity of the wave involved in the Doppler effect:
Margarita [4]

The Doppler Effect provides the equation for the calculation of apparent frequency:

f=fo[vo/(vo-vr)] 

where:<span>
vo=source wave velocity 
vr=relative speed between source and observer 
f=apparent frequency 
fo=source frequency </span>

<span>
The velocity of the doppler wave is 
v=λf</span>

where λ is light wavelength. Hence,

v=λfo[vo/(vo-vr)] 

Based on the equation, we can say that wave velocity will always be defined by one and only one wavelength.

Therefore the answer is letter C.

<span> </span>

4 0
3 years ago
Read 2 more answers
An alpha particle has a charge of +2e and a mass of 6.64 x 10-27 kg. It is accelerated from rest through a potential difference
kondor19780726 [428]

Answer:

a) v = 1.075*10^7 m/s

b) FB = 7.57*10^-12 N

c) r = 10.1 cm

Explanation:

(a) To find the speed of the alpha particle you use the following formula for the kinetic energy:

K=qV          (1)

q: charge of the particle = 2e = 2(1.6*10^-19 C) = 3.2*10^-19 C

V: potential difference = 1.2*10^6 V

You replace the values of the parameters in the equation (1):

K=(3.2*10^{-19}C)(1.2*10^6V)=3.84*10^{-13}J

The kinetic energy of the particle is also:

K=\frac{1}{2}mv^2       (2)

m: mass of the particle = 6.64*10^⁻27 kg

You solve the last equation for v:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(3.84*10^{-13}J)}{6.64*10^{-27}kg}}\\\\v=1.075*10^7\frac{m}{s}

the sped of the alpha particle is 1.075*10^6 m/s

b) The magnetic force on the particle is given by:

|F_B|=qvBsin(\theta)

B: magnitude of the magnetic field = 2.2 T

The direction of the motion of the particle is perpendicular to the direction of the magnetic field. Then sinθ = 1

|F_B|=(3.2*10^{-19}C)(1.075*10^6m/s)(2.2T)=7.57*10^{-12}N

the force exerted by the magnetic field on the particle is 7.57*10^-12 N

c) The particle describes a circumference with a radius given by:

r=\frac{mv}{qB}=\frac{(6.64*10^{-27}kg)(1.075*10^7m/s)}{(3.2*10^{-19}C)(2.2T)}\\\\r=0.101m=10.1cm

the radius of the trajectory of the electron is 10.1 cm

6 0
3 years ago
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