Question

Jessica and Martin start riding their bicycles towards each other at 2 pm. At 2 pm, they are 25 miles apart. Jessica rides her bike at a constant rate of 15 miles per hour and Martin rides his at a constant rate of 10 miles per hour. At 2 pm, a bird starts flying towards Martin. As soon as the bird gets to Martin, it turns back around and flies towards Jessica, and continues going back and forth until Jessica and Martin meet. The bird travels at a constant rate of 45 miles per hour. How far does the bird fly from the time it starts until Jessica and Martin meet

Answer 1

Answer:

45 miles

Explanation:

Speed of Jessica = 15 mph

Speed of Martin = 10 mph

Distance between them = 25 miles

Time they both will be cycling is the same = t (Assuming they started at the same time and stop at the same time they meet)

Speed of bird = 45 mph

Distance = Speed × Time

$15t+10t=25\\\Rightarrow 25t=25\\\Rightarrow t=\frac{25}{25}\\\Rightarrow t=1\ h$

Let us assume the bird started at the same position as Jessica

It keeps going back and forth between them for hour till they meet at constant speed

$Distance=45\times 1=45\ miles$

The distance the bird traveled is 45 miles