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lesantik [10]
3 years ago
11

1. A car starting from rest accelerates uniformly at 3

Physics
1 answer:
amid [387]3 years ago
5 0

The car's final speed in  m/s after the acceleration is 30.

<u />

<u>Given the following data:</u>

  • Initial velocity, U = 0 m/s (since the cars starts from rest)
  • Time, t = 10 seconds
  • Acceleration, a = 3 meter per seconds square.

To find the car's final speed in  m/s after the acceleration, we would use the first equation of motion;

Mathematically, the first equation of motion is given by the formula;

V = U + at\\\\V = 0 + 3(10)

<em>Final speed, V </em><em>=</em><em> 30 m/s</em>

Therefore, the car's final speed in  m/s after the acceleration is 30.

Read more: brainly.com/question/8898885

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If an athlete expends 3480. kJ/h, how long does she have to play to work off 1.00 lb of body fat? Note that the nutritional calo
Sunny_sXe [5.5K]

Answer:

The time required by the Athlete to work off 1.00 lb of body fat = 0.296 minute

Explanation:

1 lb of body fat = 4.1 k cal

1 k cal = 4.184 Kilo joule

1 lb of body fat = 4.1 × 4.184 = 17.1544 Kilo joule

Athlete expends 3480 Kilo joule in one hour

⇒ Time required to expand 3480 Kilo joule  = 60 minute

⇒ Time required to expand 1 Kilo joule = \frac{60}{3480} \frac{min}{KJ}

⇒ Time required to expand 17.1544 Kilo joule = \frac{60}{3480} × 17.1544 = 0.296 min

Therefore the time required by the Athlete to work off 1.00 lb of body fat = 0.296 minute

6 0
3 years ago
10. How much work is done by gravity if it pulls a 100 N object down 2 m?
NeTakaya

Answer:

200 J

Explanation:

W = f * d

W = 100N * 2m

W = 200 J

5 0
3 years ago
A 2.81 μF capacitor is charged to 1220 V and a 6.61 μF capacitor is charged to 560 V. These capacitors are then disconnected fro
fenix001 [56]

Answer:

756.88 Volts will be the potential difference across each capacitor.

Explanation:

Q=C\times V

Q = Charge on capacitor

C = Capacitance

V = Voltage across capacitor

Capacitance of first capacitor = C_1=2.81 \mu F=2.81\times 10^{-6} F

Charge of first capacitor = Q_1

Voltage across first capacitor = V_1=1220 V

Q_1=C_1V_1

Q_1=2.81\times 10^{-6} F\times 1220 V=0.0034282 C

Capacitance of first capacitor = C_2=6.61\mu F=6.61\times 10^{-6} F

Charge of second capacitor = Q_2

Voltage across first capacitor = V_2=560 V

Q_2=C_2V_2

Q_1=6.61\times 10^{-6} F\times 560 V=0.0037016 C

Both the capacitors are disconnected and positive plates are now connected to each other and the negative plates are connected to each other. These capacitors are connected in parallel combination.

Total charge = Q

Q =Q_1+Q_2=0.0034282 C+ 0.0037016 C=0.0071298 C

Total capacitance in parallel combination:

C_p=C_1+C_2=2.81\times 10^{-6} F+6.61\times 10^{-6} F=9.42\times 10^{-6} F

Potential across both capacitors = V

V=\frac{Q}{C}=\frac{0.0071298 C}{9.42\times 10^{-6} F}=756.88 V

756.88 Volts will be the potential difference across each capacitor.

8 0
3 years ago
Science and technology are closely related, but not the same. Which of the following is most likely a result of technology, not
zavuch27 [327]

The answer is invention. Technology is vital to science for purposes of dimension, data gathering, treatment of samples, calculation, transport to research sites, defense from hazardous materials, and communication. So technology is new tools and techniques that are being industrialized that make it conceivable to progress various lines of scientific investigation.

8 0
4 years ago
Read 2 more answers
Suppose you are asked to find 91,321,972×0.007004. Doing a quick estimate by rounding the numbers in scientific notation, what v
slamgirl [31]

Answer:

Product, P=9.1321972\times 10^7\times 7.004\times 10^{-3}

P = 639619.091888

Explanation:

In this case, we need to find the product of two numbers. These are as follows :

N_1=91321972=9.13\times 10^7

N_2=0.007004=7.004\times 10^{-3}

On doing calculation, we get the product of two numbers as :

P=N_1\times N_2

P=9.1321972\times 10^7\times 7.004\times 10^{-3}

P = 639619.091888

In scientific notation the product of two number is given by :

P=63\times 10^4

Hence, this is the required solution.

3 0
3 years ago
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