1. A car starting from rest accelerates uniformly at 3
1 answer:
The car's final speed in m/s after the acceleration is 30.
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<u>Given the following data:</u>
- Initial velocity, U = 0 m/s (since the cars starts from rest)
- Time, t = 10 seconds
- Acceleration, a = 3 meter per seconds square.
To find the car's final speed in m/s after the acceleration, we would use the first equation of motion;
Mathematically, the first equation of motion is given by the formula;
<em>Final speed, V </em><em>=</em><em> 30 m/s</em>
Therefore, the car's final speed in m/s after the acceleration is 30.
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Answer:
The answer is .
Explanation:
From the law of gravity,
considering F as a conservative force, ,
the general expression for gravitational potential energy is
,
where G is the gravitational constant, M and m are the mass of the attracting bodies, and r is the distance between their centers. The negative sign is because the force approaches zero for large distances, and we choose the zero of gravitational potential energy at an infinite distance away.
However, as the mass of the Sun is much greater than the mass of the rock, the gravitational acceleration is defined as
,
(the negative sign indicates that the force is an attractive force), and the potential energy between the rock and the Sun is
,
which is actually the total energy of the system, because the rock materializes stationary at this point (there is no radial kinetic energy).
When the rock hits the surface of the Sun, almost all potential energy is converted to kinetic energy, but not all because the Sun is not a puntual mass. So the potential energy converted to kinetic energy is
,
then, the kinetik energy when the rock hits the surface is
,
so
where g is the gravitational acceleration generated by the Sun at R,
.