All categories

2 years ago

1. A car starting from rest accelerates uniformly at 3

Physics

1 answer:

amid [387]2 years ago

5 0

The car's final speed in m/s after the acceleration is 30.

Given the following data:

Initial velocity, U = 0 m/s (since the cars starts from rest)

Time, t = 10 seconds

Acceleration, a = 3 meter per seconds square.

To find the car's final speed in m/s after the acceleration, we would use the first equation of motion;

Mathematically, the first equation of motion is given by the formula;

$V = U + at\\\\V = 0 + 3(10)$

Final speed, V = 30 m/s

Therefore, the car's final speed in m/s after the acceleration is 30.

You might be interested in

An astronaut on Earth notes that in her soft drink an ice cube floats with 9/10 of its volume submerged. If she were instead in

riadik2000 [5.3K]

Answer:

B) with 9/10 submerged

Explanation:

$m$ = mass of ice cube

$\rho$ = density of soft drink

$V$ = Volume of soft drink displaced

ice cube floats in the soft drink when the force of buoyancy on it balances its weight. Force of buoyancy acting on the cube in upward direction is same as the weight of the soft drink displaced. hence we can write

weight of ice cube = weight of soft drink displaced

$mg = \rho V g$

$m = \rho V$

we see that the acceleration due to gravity cancel out both side and hence it does affect as astronaut is on earth on in a lunar module.

8 0

3 years ago

Read 2 more answers

Distance meters Time (seconds) Trial Tria 2 Trials Average 3 053 059 0.52 055 6 106 719 104 Uning the values trom the data table

kumpel [21]

Jsisisusuagahannananana this is worth 22 points g that’s crazy 25

5 0

1 year ago

You have 2 minutes to get to PE from science class before you get a tardy. If PE is 100m away and you walk at a speed of 1.1m/s

mart [117]

Answer:

Explanation:

4 0

3 years ago

Read 2 more answers

a car travels at 15 m/s for 10 s. It then speeds up with a constant acceleration of 2.0 m/s? for 15 s. At the end of this time,

Firlakuza [10]

V = u + at where u is initial velocity (15 m/s), a is acceleration (2m/s^2) and t is time (15 seconds)

V = 15 + 2 X 15

V = 45 m/s

6 0

2 years ago

An astronaut has a mass of 75 kg and is floating in space 500 m from his 125,000 kg spacecraft. What will be the force of gravit

nikdorinn [45]

Answer:

1. 2.5×10¯⁹ N

2. 3.33×10¯¹¹ m/s²

Explanation:

1. Determination of the force of attraction.

Mass of astronaut (M₁) = 75 Kg

Mass of spacecraft (M₂) = 125000 Kg

Distance apart (r) = 500 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force of attraction (F) =?

The force of attraction between the astronaut and his spacecraft can be obtained as follow:

F = GM₁M₂ /r²

F = 6.67×10¯¹¹ × 75 × 125000 / 500²

F = 2.5×10¯⁹ N

Thus, the force of attraction between the astronaut and his spacecraft is 2.5×10¯⁹ N

2. Determination of the acceleration of the astronaut.

Mass of astronaut (m) = 75 Kg

Force (F) = 2.5×10¯⁹ N

Acceleration (a) of astronaut =?

The acceleration of the astronaut can be obtained as follow:

F = ma

2.5×10¯⁹ N = 75 × a

Divide both side by 75

a = 2.5×10¯⁹ / 75

a = 3.33×10¯¹¹ m/s²

Thus, the acceleration the astronaut is 3.33×10¯¹¹ m/s²

5 0

2 years ago