1 kilo joule = 0.239006 calories
134 kilo joule = 134 x 0.239006
= 32.026804 calories
Answer: It takes 3.120 seconds for the concentration of A to decrease from 0.860 M to 0.260 M.
Explanation:
Integrated rate law for second order kinetics is given by:
k = rate constant = 
= initial concentration = 0.860 M
a= concentration left after time t = 0.260 M
Thus it takes 3.120 seconds for the concentration of A to decrease from 0.860 M to 0.260 M.
Answer:
The carbons on either side of the double bond are pointed in the same direction
Answer:
The both compounds are different.
Explanation:
In order to confirm weather both compounds are same we will check the mole ration. If it is same the compounds will be same.
Given data:
For compound 1.
Mass of hydrogen = 15 g
Mass of oxygen = 120 g
Moles of hydrogen and oxygen = ?
Number of moles of hydrogen = 15 g/ 1g/mol = 15 mol
Number of moles of oxygen = 120 g/ 16 g/mol = 7.5 mol
Total number of moles = 22.5 mol
% of hydrogen = 15 /22.5 × 100 = 66.7%
% of oxygen = 7.5 / 22.5× 100 = 33.3%
For compound 2:
Mass of hydrogen = 2 g
Mass of oxygen = 32 g
Moles of hydrogen and oxygen = ?
Number of moles of hydrogen = 2 g/ 1g/mol = 2 mol
Number of moles of oxygen = 32 g/ 16 g/mol = 2 mol
Total number of moles = 4 mol
% of hydrogen = 2 /4 × 100 = 50%
% of oxygen = 2 / 4× 100 = 50%
Answer:
Density of concentrated H2SO4 = 1.99g/cm^3 = 1991.79Kg/m^3
Explanation:
mass of empty flask = 78.23g mass of flask filled when with water = 593.63g.
mass of flask filled when with concentrateds sulfuric acid, H2SO4 = 1026.57g
Mass of water = (mass of flask filled when with water) -
(mass of empty flask) = 593.63g - 78.23g = 515.4g
Volume of flask = volume of water = volume of concentrateds sulfuric acid, H2SO4 =
(mass of water)/ density of water) = 515.4g/1.00g/cm^3 = 515.4cm^3
The density of concentrated sulfuric acid is given by
Density of concentrated H2SO4 = (mass of H2SO4) ÷ (volume of H2SO4) = 1026.57g/515.4cm^3 = 1.99g/cm^3 = 1991.79Kg/m^3
