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yanalaym [24]
3 years ago
5

What are atoms comprised of?

Chemistry
1 answer:
inessss [21]3 years ago
8 0

Answer:

Protons, Neutrons, and Electrons

Explanation:

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A- is a weak base. which equilibrium corresponds to the equilibrium constant ka for ha?
vekshin1

Answer:

K_a=\frac{[H^+][A^-]}{[HA]}

Explanation:

ka is defined as the dissociation constant of an acid. It is defined as the ratio of concentration of products to the concentration of reactants.

For the dissociation of weak acid, the chemical equation follows:

HA\rightleftharpoons H^++A^-

The equilibrium constant is defined by the equilibrium concentration of products over reactants:

K_a=\frac{[H^+][A^-]}{[HA]}

5 0
3 years ago
BRANILEST IF RIGHT <br><br> WAVE A OR B
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I think it’s A but I’m not sure.
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The heat required to change 1 gram of a solid at its normal melting point to a liquid at the same temperature is called the heat
Darya [45]

Answer:

Heat of fusion

Explanation:

The heat required to change 1 gram of a solid at its normal melting point to a liquid at the same temperature is called the heat of fusion.

The formula for the heat of fusion is given by :

\Delta H=n\Delta H_{fus}

Where

n is no of moles

\Delta H_{fus} is molar heat of the substance

Hence, the correct answer is heat of fusion

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3 years ago
students calculated the circumference of a globe to be 60.0 cm. The actual circumference of the glide is 63 cm. The percent devi
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A gas has a pressure of 1.34 atm when the temperature is 237K. The gas is then heated until the temperature measures 312K. What
alexandr1967 [171]

The answer for the following question is answered below.

  • <em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>

Explanation:

Given:

Initial pressure of the gas = 1.34 atm

Initial temperature of the gas = 273 K

final temperature of the gas = 312 K

To solve:

Final temperature of the gas

We know;

From the ideal gas equation

P × V = n × R × T

So;

from the above equation we can say that

    <em>P ∝ T</em>

     \frac{P}{T} = constant  

     \frac{P_{1} }{P_{2} } = \frac{T_{1} }{T_{2} }

Where;

P_{1} = initial pressure of a gas

P_{2} = final pressure of a gas

T_{1} = initial temperature of a gas

T_{2} = final temperature of  a gas

    P_{2} = \frac{1.34*312}{237}

    P_{2}  = 1.76 atm

<em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>

6 0
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