a) 1 mole of Ne
b) i/2 mole of Mg
c) 1570 moles of Pb.
d) 2.18125*10^-13 moles of oxygen.
Explanation:
The number of moles calculated by Avogadro's number in 6.23*10^23 of Neon.
6.23*10^23= 1/ 6.23*10^23
= 1 mole
The number of moles calculated by Avogadro's number in 3.01*10^23 of Mg
3.2*10^23=1/6.23*10^23
= 1/2 moles of Pb.
Number of moles in 3.25*10^5 gm of lead.
atomic weight of Pb=
n=weight/atomic weight
= 3.25*10^5/ 207
= 1570 moles of Pb.
Number of moles 4.50 x 10-12 g O
number of moles= 4.50*10^-12/16
= 2.18125*10^-13 moles of oxygen.
Answer:
Ice Cubes. When water freezes into ice cubes, the energy is released in the form of heat. ...
Formation Of Snow In Clouds. Sponsored. ...
Hot Packs. ...
Rusting Of Iron. ...
Burning Of Candles. ...
Lightning Of Match. ...
Setting Cement And Concrete.
Explanation:
Question:
Layer 1 and 2 → Animal fossil
Layer 3 and 4 → First plant fossil
Layer 5 → Animal fossil
Layer 6→ Second plant fossil
Layer 7 → Animal fossil.
Answer:
The correct option to choose answer is;
C) Layers 3 and 4 (Secondary succession layer).
Explanation:
Secondary succession is a concept related to pliant life and it describes the notion of an ecosystem regenerates after being destroyed and it takes place when the level of disruption is not enough to do away with all present vegetation and present soil from a location.
Secondary succession is started by an incident that destroys to a large extent the present ecosystem. Events that start secondary succession includes;
1) Hurricane
2) Fire and
3) Harvesting.
Answer:
~Na+1 is already in the preferred form. Because of this, the second ionization energy of sodium is higher than normal. Mg+1 loses an electron to form s2 p6 .
Answer : The balanced reaction in acidic solution is,
Explanation :
The given partial equation is,
First we have to separate into half reaction. The two half reactions are:
Now we have to balance the half reactions in acidic medium, we get:
............(1)
............(2)
Now we have to balance the electrons of the half reactions. When we are multiplying the equation (1) by 2, we get
...........(3)
Now we have to add both the half reactions (2) and (3), we get the final balanced chemical reaction.
