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3 years ago

1. Why does CH30 evaporate faster than water?

Chemistry

1 answer:

Iteru [2.4K]3 years ago

8 0

Answer:

Becuase CH30 has weaker inter-molecular forces

Explanation:

Becuase its intermolecular forces are weaker the particals will seperate more easilyl.

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A sample of a compound is determined to have 1.17 g of carbon and 0.287 g of hydrogen. what is the correct representation of the

yarga [219]

CH3 is the empirical formula for the compound.

A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.

The number of atom or moles in the compound is

1.17 g C X 1 mol of C / 12.011 g C = 0.097411 mol of C.

0.287 g H x 1 mol of H / 1 g H = 0.28474 mol H.

This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.

So we can represent the compound with the formula C0.974H0.284.

Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.

we can divide 0.284 by 0.0974.

0.284 / 0.0974 = 3.

So here, Carbon is one and hydrogen is 3.

We can write the above formula as a CH3.

Hence the empirical formula for the sample compound is CH3.

For a detailed study of the empirical formula refer given link brainly.com/question/13058832.

#SPJ1.

5 0

1 year ago

How do elements differ going from left to right across a period on the periodic table?

Nuetrik [128]

Their atomic number increases

6 0

2 years ago

State what method you would use the separate water from a potassium iodide solution

tia_tia [17]

Answer:

<u>distillation</u> is the method used to separate water from a potassium iodine solution

Explanation:

hope it helps !!

4 0

3 years ago

Read 2 more answers

Lead can be prepared from galena [lead(II) sulfide] by first roasting the galena in oxygen gas to form lead(II) oxide and sulfur

Vesna [10]

Answer:

a) Step 1:

$2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)$

Step 2:

$2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)$

b) The overall balanced reaction for given process is ;

$3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)$

Explanation:

Galena = $PbS$

Lead(II) oxide = $PbO$

Sulfur dioxide = $SO_2$

Step 1:

Roasting the galena in oxygen gas to form lead(II) oxide and sulfur dioxide.

Balanced equation of step 1:

$2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)$ ..[1]

Step 2:

Heating the metal oxide with more galena forms the molten metal and more sulfur dioxide.

Balanced equation of step 2:

$2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)$ ..[2]

For over all reaction add [1] and [2]. The overall balanced reaction for given process is ;

$3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)$

5 0

3 years ago

Read 2 more answers

A mixture containing nitrogen, hydrogen, and iodine established the following equilibrium at 400 °C:2NH3(g) + 3I2(g) ⇌ N2(g) + 6

miss Akunina [59]

Answer: The value of $K_{c}$ for this reaction is 250000.

Explanation:

The given equation is as follows.

$2NH_{3}(g) + 3I_{2}(g) \rightleftharpoons N_{2}(g) + 6HI(g)$

$N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g); K_{c_{1}} = 0.50$ ... (1)

$H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g); K_{c_{2}} = 50$ ... (2)

To balance the atoms, multiply equation (2) by 3. Hence, the equation (2) can be re-written as follows.

$3H_{2}(g) + 3I_{2}(g) \rightleftharpoons 6HI(g); K_{c_{2}} = (50)^{3}$ ... (3)

Now, subtract equation (1) from equation (3). So, the equation formed will be as follows.

$3I_{2} - N_{2} \rightleftharpoons 6HI - 2NH_{3}$

This equation can also be re-written as follows.

$3I_{2} + 2NH_{3} \rightleftharpoons N_{2} + 6HI$

This equation is similar to the equilibrium equation given to us.

Therefore, during this subtraction the equation constants get divided as follows.

$K^{'}_{c} = \frac{K_{c_{2}}}{K_{c_{1}}}\\= \frac{(50)^{3}}{0.50}\\= 250000$

Thus, we can conclude that the value of $K_{c}$ for this reaction is 250000.

6 0

2 years ago