Elementary charge used to determine charges of other objects is equal to a charge of electron or proton. It's value is roughly
. All other charges are whole-number multipliers of this elementary charge, meaning that we multiply elementary charge by {...,-2,-1,0,1,2,...}.
To find out if the measured charge can be accepted we need to divide it with elementary charge to see if we get whole number as result.
There are three possible values of measured charge:
As we can see none of the possible values of a measured charge is whole-number multiplier of elementary charge so the researcher should not accept the value.
This charge can be achieved by using quarks which have value of 1/3 of elementary charge but they do not remain stable for long enough.
To solve this problem it will be necessary to apply the concepts related to the electric potential in terms of the variation of the current and inductance. From this definition, we will start to find the load, which is dependent on the current as a function of time.
Here,
L = Inductance
Rate of change of current
If we take the equation and put the variation of the current as a function of time, in terms of the voltage in terms of the inductance we would have
The current as a function of time will be then,
The charge is the integral of the current in each variation of the time, then
Equation the terms we will have,
Answer:
10 m/s
Explanation:
Momentum before collision = momentum after collision
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(8 kg)(8 m/s) + (6 kg)(6 m/s) = (8 kg)(5 m/s) + (6 kg) v
64 kg m/s + 36 kg m/s = 40 kg m/s + (6 kg) v
60 kg m/s = (6 kg) v
v = 10 m/s
Answer:
1) T = 4.5 s
2) T = 4.5 s
3) v = 9.9 m/s
Explanation:
We can use the equation
T = 2π√(L/g)
1) T = 2π√(5m/9.81 m/s²) = 4.5 s
2) T = 2π√(L/g)
T = 2π√(5m/9.81 m/s²) = 4.5 s
3) v = √(2gR)
v = √(2(9.81 m/s²)(5m))
v = 9.9 m/s