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agasfer [191]
3 years ago
10

Define Simple harmonic motion (SHM). A body moving with SHM has an amplitude of 10 cm and a frequency of 100 Hz. Find (a) the pe

riod of oscillation (b) the acceleration at the maximum displacement (c) the velocity at the centre of motion.
Physics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

Explanation:

Simple harmonic motion is the motion that involves the cyclic and periodic motion of an object about a central point or equilibrium position, due to the effect of a restoring force, such that the object has the same maximum displacement during its motion on either side of the equilibrium point

(a) The parameters of the body moving with SHM are;

The amplitude of the motion of the body, a = 10 cm

The frequency of the complete cycles of the motion of the body, f = 100 Hz

The period of the oscillation, 'T', is the time it takes o complete one cycle

T = 1/f

∴ T = 1/100 Hz = 0.01 seconds

(b) The acceleration, a = -A·ω²·sin(ω·t)

Where;

One complete oscillation is given as ω·t = 2·π

Therefore at either end at the maximum displacement, which is at either end of the equilibrium position is reached at half a complete cycle, or ω·t = 2·π/2 = π

At the maximum displacement a = -A·ω²·sin(ω·t) = A·ω²·sin(π) = 0

Therefore, we have;

The acceleration, of the body at the maximum displacement, a = 0 m/s².

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Answer:

The work is -67.76 J

Explanation:

The law of conservation of energy is considered one of one of the fundamental laws of physics and states that the total energy of an isolated system remains constant. except when it is transformed into other types of energy.

This is summed up in the principle that energy can neither be created nor destroyed in the universe, only transformed into other forms of energy.

In this case you must calculate the loss of kinetic energy. This loss is actually the work done against the resistive force in the air. Friction is the only force other than gravity that acts on the ball.

So, the loss of kinetic energy is \frac{1}{2} *m*(vf^{2} -vi^{2} )

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Final velocity of the ball: vf= 15 \frac{m}{s}

Replacing:

\frac{1}{2} *0.22 kg*(15^{2} -29^{2} )= -67.76 J

Friction work is always negative because friction is always against displacement.

<u><em>The work is -67.76 J</em></u>

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