H2o means water and co3 is co-signs
The half-life equation is written as:
An = Aoe^-kt
We use this equation for the solution. We do as follows:
5.5 = 176e^-k(165)
k = 0.02
<span>What is the half-life of the goo in minutes?
</span>
0.5 = e^-0.02t
t = 34.66 minutes <----HALF-LIFE
Find a formula for G(t) , the amount of goo remaining at time t.G(t)=?
G(t) = 176e^-0.02t
How many grams of goo will remain after 50 minutes?
G(t) = 176e^-0.02(50) = 64.75 g
Answer: A. True
Explanation:
I'm not all the way sure, so please don't hate on me. I looked it up to double check and it should be true.
!PLEASE NOT HATE IF IT'S WRONG!
Answer:
Explanation:
A protein is a long chain of amino acids linked together by amide groups.
The general structure is
![\rm \left[-NHCHR-\underbrace{\hbox{CO-NH}}_{\hbox{amide group}}-CHRCO-\right]_{n}](https://tex.z-dn.net/?f=%5Crm%20%5Cleft%5B-NHCHR-%5Cunderbrace%7B%5Chbox%7BCO-NH%7D%7D_%7B%5Chbox%7Bamide%20group%7D%7D-CHRCO-%5Cright%5D_%7Bn%7D)
Answer: -
C. The hydrogen at 10 °C has slower-moving molecules than the sample at 350 K.
Explanation: -
The kinetic energy of gas molecules increase with the increase in the temperature of the gas. With the increase in kinetic energy, the gas molecules also move faster. Thus with the increase of temperature, the speed of the molecules increase.
Temperature of first hydrogen gas sample is 10 °C.
10 °C means 273+10 = 283 K
Thus first sample temperature = 283 K
The second sample temperature of the hydrogen gas is 350 K.
Thus the temperature is increased.
So both the kinetic energy and speed of molecules is more for the hydrogen gas sample at 350 K.
Thus the hydrogen at 10 °C has slower-moving molecules than the sample at 350 K.
Hence the answer is C.
