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PtichkaEL [24]
3 years ago
10

[C]utting programs that were not effective or essential and even some that were, but are now unaffordable; and precisely targeti

ng our investments. Every department will feel the impact of these reductions as they cut programs or tighten their belts to free up more resources for areas critical to economic growth. —President Barack Obama,
2012 Budget Message of the President

In this statement, which type of spending is President Obama referring to? A)mandatory
B)discretionary 
C)interest
D)tax
The correct answer is B)discretionary
Physics
2 answers:
alukav5142 [94]3 years ago
5 0

Answer:

D. Discretionary

zalisa [80]3 years ago
3 0

Option B i.e discretion is the right and correct answer.

[C]utting programs that were not effective or essential and even some that were, but are now unaffordable; and precisely targeting our investments. Every department will feel the impact of these reductions as they cut programs or tighten their belts to free up more resources for areas critical to economic growth. —President Barack Obama, 2012 Budget Message of the President.

The President above clearly refers to the Discretion Spending where portion of the budget is decided by Congress through the annual appropriations.

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Read 2 more answers
Six artificial satellites circle a space station at constant speed. The mass m of each satellite, distance L from the space stat
nikklg [1K]

Answers:

a) T_{2}>T_{5}>T_{1}>T_{3}=T_{6}>T_{4}

b) a_{4}>a_{6}>a_{1}>a_{3}>a_{5}>a_{2}

Explanation:

a) Since we are told the satellites circle the space station at constant speed, we can assume they follow a uniform circular motion and their tangential speeds V are given by:

V=\omega L=\frac{2\pi}{T} L (1)

Where:

\omega is the angular frequency

L is the radius of the orbit of each satellite

T is the period of the orbit of each satellite

Isolating T:

T=\frac{2 \pi L}{V} (2)

Applying this equation to each satellite:

T_{1}=\frac{2 \pi L}{V_{1}}=261.79 s (3)

T_{2}=\frac{2 \pi L}{V_{2}}=1570.79 s (4)

T_{3}=\frac{2 \pi L}{V_{3}}=196.349 s (5)

T_{4}=\frac{2 \pi L}{V_{4}}=98.174 s (6)

T_{5}=\frac{2 \pi L}{V_{5}}=785.398 s (7)

T_{6}=\frac{2 \pi L}{V_{6}}=196.349 s (8)

Ordering this periods from largest to smallest:

T_{2}>T_{5}>T_{1}>T_{3}=T_{6}>T_{4}

b) Acceleration a is defined as the variation of velocity in time:

a=\frac{V}{T} (9)

Applying this equation to each satellite:

a_{1}=\frac{V_{1}}{T_{1}}=0.458 m/s^{2} (10)

a_{2}=\frac{V_{2}}{T_{2}}=0.0254 m/s^{2} (11)

a_{3}=\frac{V_{3}}{T_{3}}=0.4074 m/s^{2} (12)

a_{4}=\frac{V_{4}}{T_{4}}=1.629 m/s^{2} (13)

a_{5}=\frac{V_{5}}{T_{5}}=0.101 m/s^{2} (14)

a_{6}=\frac{V_{6}}{T_{6}}=0.814 m/s^{2} (15)

Ordering this acceerations from largest to smallest:

a_{4}>a_{6}>a_{1}>a_{3}>a_{5}>a_{2}

4 0
3 years ago
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Answer:

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