Question

how many grams of silver medal could be recovered from a reaction of 50 g silver nitrate and copper metal

Answer 1

Answer:

Answer is: mass of copper is 127 grams.

Balanced chemical reaction: Cu(s) + 2AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s).

m(Ag) = 432 g.

n(Ag) = m(Ag) ÷ M(Ag).

n(Ag) = 432 g ÷ 108 g/mol.

n(Ag) = 4 mol.

From chemical reaction: n(Ag) : n(Cu) = 2 : 1.

n(Cu) = 4 mol ÷ 2 = 2 mol.

m(Cu) = n(Cu) · M(Cu).

m(Cu) = 2 mol · 63.5 g/mol.

m(Cu) = 127 g

Explanation: