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andrew-mc [135]
3 years ago
12

What is the temperature (in K) of 16.45 moles of methane gas in a 4.95 L container at 4.68 atm?

Chemistry
1 answer:
AlexFokin [52]3 years ago
4 0
Using the ideal gas law: PV=nRT
      P is pressure; V is volume; n is the amount in moles; R=0.082; T is temperature in K.

(4.68)*(4.95)=(16.45)*(0.0821)*T
Solve for T. 
T=17.15
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