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tekilochka [14]
3 years ago
12

Particles in a plasma experience collisions than particles in a solid. Based on their state of matter alone, is it easier to spe

ak of the shape of the Sun or the Moon? Two unknown substances are in identical beakers. One is a solid and the other is a plasma. If you were given a scale to allow you to obtain the mass of the substance, and had to guess based on mass alone, you would say that the plasma is in the beaker.
Chemistry
2 answers:
xxMikexx [17]3 years ago
5 0
More, Moon, and lighter, you're welcome
lesya [120]3 years ago
3 0

Particles in a plasma experience more collisions than particles in a solid.

Based on their state of matter alone, is it easier to speak of the shape of the Sun or the Moon?   moon


Two unknown substances are in identical beakers. One is a solid and the other is a plasma. If you were given a scale to allow you to obtain the mass of the substance, and had to guess based on mass alone, you would say that the plasma is in the lighter beaker.


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Which of the following oils would consume the greatest number of equivalents of hydrogen when subject to catalytic hydrogenation
Murljashka [212]

Answer: Option (B) is the correct answer.

Explanation:

When a fatty acid contains high number of double bonds then its unsaturation will also be high and hence, it will consume greater number of equivalents of hydrogen.

In corn oil, there are no unsaturated sites are present.

In olive oil, there is one unsaturated site with majority of oleic acid. In olive oil, there are more than 70% of total unsaturated oils.

In lard oil, there are around 60% of unsaturated oils.

In herring oil, there are highest number of saturated fatty acids and lowest polyunsaturated acids.

Thus, we can conclude that out of the given options, olive oils would consume the greatest number of equivalents of hydrogen when subject to catalytic hydrogenation.

5 0
4 years ago
Based on table N of the reference tables what is the number of hours required for 42k (potassium -42) to undergo three half-life
skelet666 [1.2K]

The number of hours required : 37.2 hours

<h3>Further explanation</h3>

Given

⁴²K (potassium -42)

Required

The number of hours

Solution

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually, radioactive elements have an unstable atomic nucleus.  

Based on Table N(attached), the half-life for ⁴²K is 12.4 hours, which means half of a sample of ⁴²K will decay in 12.4 hours

For three half-life periods :

\tt 3\times 12.4=37.2~hours

3 0
3 years ago
Please help! will mark brainliest
Step2247 [10]

Answer:

add me!!!

Explanation:

my insta is: becomewhatyouwant2inlife

3 0
3 years ago
Find the formula for the hydrate<br>0.737 g MgSO3 and 0.763 g H2O
babunello [35]

The required formula of hydrate is MgSO₃.6H₂O.

<h3>How do we calculate the formula of hydrate?</h3>

The number of moles of water per mole of anhydrous solid (x) will be computed by dividing the number of moles of water by the number of moles of anhydrous solid (x) to find the hydrate's formula.

Moles will be calculated as:
n = W/M, where

  • W = given mass
  • M = molar mass

Moles of MgSO₃ = 0.737g / 104.3g/mol = 0.007mol

Moles of H₂O = 0.763g / 18g/mol = 0.04 mol

Number of H₂O molecule = 0.04/0.007 = 5.7 = 6

So formula of hydrate is MgSO₃.6H₂O.

Hence required formula of hydrate compound is MgSO₃.6H₂O.

To know more about hydrate compound, visit the below link:

brainly.com/question/22411417

#SPJ1

6 0
2 years ago
Help plz:)))I’ll mark u Brainliest
Triss [41]

Answer:

Explanation:

We want the energy required for the transition:

CO  2 ( s ) + Δ → C O 2 ( g )

Explanation:

We assume that the temperature of the gas and the solid are EQUAL.

And thus we simply have to work out the product:

2 × 10^ 3 ⋅ g × 196.3 ⋅ J ⋅ g − 1  to get an answer in  Joules  as required.

What would be the energy change for the reverse transition:

C O 2 ( g ) + → C O 2 ( s ) ?

6 0
3 years ago
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