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Katen [24]
3 years ago
8

Suppose that 7.25 x 10^22 atoms of a hypothetical element have a mass of 3.88 g. What would be the molar mass (g/mol) of this el

ement ? Correct number of sig figs are required.
Chemistry
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

32.23 to 4 significant figures.

Explanation:

The molar mass of the element is the mass of 6.022 * 10^23 atoms (Avogadro's number).

So by proportion it is 6.022 * 10^23 * 3.88 / 7.25 * 10^22

= 32.23 to 4 significant figures.

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SHOW WORK
stealth61 [152]
PV = nRT —> n = PV/RT

P = 2.90 atm
V = 4.80 L
R = 0.08206 L atm / mol K
T = 62.0 + 273 = 335 K (make sure you convert from celsius to kelvin)

n = (2.90 • 4.80) / (0.08206 • 335) = 0.506 moles of gas
4 0
3 years ago
Which of the following coefficients is needed to balance the combustion reaction of methane? a.3 b.2 c.4 d.equation is already b
Alla [95]
I might go with d it seems right to me hope this helps.

3 0
3 years ago
The oxygen atom is smaller than the sulfur atom because _____(1) the outer electrons of oxygen are more effectively screened fro
Romashka [77]

Answer: Option (2) is the correct answer.

Explanation:

Atomic number of oxygen atom is 8 and its electronic distribution is 2, 6. So, it contains only 2 orbitals which are closer to the nucleus of the atom.

As a result, the valence electrons are pulled closer by the nucleus of oxygen atom due to which there occurs a decrease in atomic size of the atom.

Whereas atomic number of sulfur is 16 and its electronic distribution is 2, 8, 6. As there are more number of orbitals present in a sulfur atom so, the valence electrons are away from the nucleus of the atom.

Hence, there is less force of attraction between nucleus of sulfur atom and its valence electrons due to which size of sulfur atom is larger than the size of oxygen atom.

Thus, we can conclude that the oxygen atom is smaller than the sulfur atom because the outer orbitals of oxygen are located closer to the nucleus than those of sulfur.

3 0
3 years ago
What mass of oxygen is needed to burn 4g of hydrogen, given the equation below
aleksandrvk [35]

32g of oxygen is required to burn 4g of hydrogen.

Define molecular mass.

A specific molecule's mass is expressed in daltons and is known as the molecular mass (m) (Da or u). Due to the varying isotopes of an element that they contain, multiple molecules of the same substance can have distinct molecular weights.

The total atomic mass of every atom in a molecule, calculated using a scale with hydrogen, carbon, nitrogen, and oxygen having atomic masses of 1, 12, 14, and 16, respectively. For instance, water has a molecular mass of 18 (2 + 16), which consists of two hydrogen atoms and one oxygen atom. known also as molecular weight.

In ,2H2+O2-----> 2H2O

H 2 molecules have a mass of 2 g/mol.

The molecular weight of oxygen is 32 g/mol.

When the chemical equation is balanced,

To totally react, 32 g of oxygen are needed for every 22=4 g of hydrogen.

To know more about molecular mass use link below:

brainly.com/question/21334167

#SPJ1

7 0
1 year ago
Which equation is set up correctly to determine the volume of a 1.5 mole sample of oxygen gas at 22°C and 100 kPa?
LenKa [72]

The volume could be calculated by using  <span>V = n RT / P </span>

In which V = Volume
n = number of Moles
R= The Gas constant
T = Temperature (ideally this would be in Kelvin, but i don't see it in the option)
P = Pressure


I believe the answer is

 <span>V = (1.5mol) (0.08205 L*kPa/K*mol) (22Celsius)/100 kPa 


</span>
6 0
3 years ago
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