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2 years ago

During energy transformation, all energy systems: are

Physics

2 answers:

romanna [79]2 years ago

4 0

B: Energy lose

I say this because in order to change they lose energy.

Tom [10]2 years ago

3 0

B: Energy lose

i say this because in order to change they lose energy.

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In each cycle, a heat engine an input of 1940 J of heat and exhausts 1480 J of heat. What is the thermal efficiency?

AleksAgata [21]

Answer:

0.237 (23.7 %)

Explanation:

The thermal efficiency of an engine is given by:

$\eta=\frac{W}{Q_{in}}$

where

W is the useful work output of the engine

$Q_{in}$ is the heat in input

Here we have:

$Q_{in}=1940 J$

and the work done is the total heat in input minus the heat exhausted:

$W=1940 J - 1480 J=460 J$

So, the efficiency is

$\eta=\frac{460 J}{1940 J}=0.237$ (23.7 %)

8 0

2 years ago

If the distance between the bounces were 1.95 m instead of 1.30 m, but the height remained at 1.30 m, which of your answers to P

Oksanka [162]

Answer:

Below is the calculation of all the required quantities. From the calculations, Vx must change, the velocity before hitting the ground must change and the angles also must change.

Explanation:

Below is an attachment that contains the calculation steps.

Thank you for reading.

7 0

2 years ago

When a low-pressure gas of hydrogen atoms is placed in a tube and a large voltage is applied to the end of the tube, the atoms w

FromTheMoon [43]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value of n is $n =7$

Explanation:

From the question we are told that

The value of m = 2

For every value of $m, n = m+ 1, m+2,m+3,....$

The modified version of Balmer's formula is $\frac{1}{\lambda} = R [\frac{1}{m^2} - \frac{1}{n^2} ]$

The Rydberg constant has a value of $R = 1.097 *10^{7} m^{-1}$

The objective of this solution is to obtain the value of n for which the wavelength of the Balmer series line is smaller than 400nm

For m = 2 and n =3

The wavelength is

$\frac{1}{\lambda } = (1.097 * 10^7)[\frac{1}{2^2} - \frac{1}{3^2} ]$

$\lambda = \frac{1}{1523611.1112}$

$\lambda = 656nm$

For m = 2 and n = 4

The wavelength is

$\frac{1}{\lambda } = (1.097 * 10^7)[\frac{1}{2^2} - \frac{1}{4^2} ]$

$\lambda = \frac{1}{2056875}$

$\lambda = 486nm$

For m = 2 and n = 5

The wavelength is

$\frac{1}{\lambda } = (1.097 * 10^7)[\frac{1}{2^2} - \frac{1}{5^2} ]$

$\lambda = \frac{1}{2303700}$

$\lambda = 434nm$

For m = 2 and n = 6

The wavelength is

$\frac{1}{\lambda } = (1.097 * 10^7)[\frac{1}{2^2} - \frac{1}{6^2} ]$

$\lambda = \frac{1}{2422222}$

$\lambda = 410nm$

For m = 2 and n = 7

The wavelength is

$\frac{1}{\lambda } = (1.097 * 10^7)[\frac{1}{2^2} - \frac{1}{7^2} ]$

$\lambda = \frac{1}{2518622}$

$\lambda = 397nm$

So the value of n is 7

7 0

2 years ago

The hill is covered in gravel so that the truck's wheels will slide up the hill instead of rolling up the hill. The coefficient

mamaluj [8]

Answer:

Explanation:

check attachment for the solution.

8 0

2 years ago

A spring has an unstretched length of

koban [17]

Answer:

24 N

Explanation:

Given,

Unstretched length or original length , x1 = 12cm

Stiffness constant, k = 8 N/cm

Load required to take spring to a length , x2 of 15cm

Recall the relation :

F = Ke

Where, e = extension

e = x2 - x1

e = (15 - 12) = 3

F = ke

F = 8 N/cm * 3cm

F = 24 N/cm*cm

F = 24 N

Hence, required load = 24 N

8 0

2 years ago