All categories

3 years ago

Doc Brown has calculated his Delorean can accelerate at a rate of 2.52 m/s/s. How

Physics

1 answer:

GREYUIT [131]3 years ago

6 0

Answer:

304.89m

Explanation:

Given

acceleration a = 2.52m/s²

final speed v = 39.2m/s

initial speed = 0m/s (car accelerates from rest)

Using the equation of motion below to get the distance of Doc brown from Marty;

v² = u²+2as

substitute the given parameters

39.2² = 0²+2(2.52)s

1536.64 = 0+5.04s

divide both sides by 5.04

1536.64/5.04 = 5.04s/5.04

rearrange the equation

5.04s/5.04 = 1536.64/5.04

s = 304.89m

Hence He and Marty must stand at 304.89m to allow the car to accelerate from rest to a speed of 39.2 m/s?

You might be interested in

A thin rod of length L and total charge Q has the nonuniform linear charge distribution λ(x)=λ0x/L, where x is measured from the

marissa [1.9K]

Answer:

Explanation:

λ(x) = λo x/ L

(a) The total charge is Q.

$Q=\int_{0}^{L}dq$

$Q=\int_{0}^{L}\frac{\lambda _{0}x}{L}dx$

$Q=\frac{\lambda _{0}}{2L}\left ( x^{2} \right )_{0}^{L}$

$Q=\frac{\lambda _{0}}{2L}$

λo = 2Q/L

(b)

Let at a distance x from the origin the charge is dq.

so, dq = (2Q/L) x/ L dx

$dq=\frac{2Qx}{L^{2}}dx$

The potential due to this small charge at a distance d to the left of origin

$dV = \frac{KdQ}{d+x}$

$\int_{0}^{V}dV = \frac{2KQ}{L^{2}}\int_{0}^{L}\frac{xdx}{d+x}$

$V = \frac{2KQ}{L^{2}}\int_{0}^{L}\left ( 1- \frac{d}{d+x}\right )dx$

$V = \frac{2KQ}{L^{2}}\times \left ( x-dln(d+x) \right )\int_{0}^{L}$

$V = \frac{2KQ}{L^{2}}\times \left ( L-dln(d+L)-0+dlnd \right )$

$V = \frac{Q}{4\pi \epsilon _{0}L^{2}}\times \left ( L+d\times ln\left (\frac{d}{d+L} \right )\right )$

4 0

2 years ago

I will give brainliest to whoever is first

Roman55 [17]

Answer:

first

Explanation:

also wat u need help with

4 0

2 years ago

A student sits in a chair that can spin without friction. The student has her hands outstretched and starts rotating at 1.9 rev/

Airida [17]

Answer:

the resulting angular speed after she pulls her hand inwards in (rad/s) is 27.02 rad/s

Explanation:

Given that :

the initial angular speed $\omega_1 = 1.9 \ \ rev/s$

Initial rotational inertia $I_1 = 12.00 \ \ kg.m^2$

Final angular speed $\omega_2 = ???$

Final rotational inertia $I_2 = 5.3 \ \ kg.m^2$

According to conservation of momentum :

Initial momentum = final momentum

$I_1 \omega_1 = I_2 \omega_2$

$\omega_2 = \frac{I_1 \omega_1}{I_2}$

$\omega_2 = \frac{12.00*1.9}{5.3}$

$\omega_2 = 4,3$ $rev/s$

To rad/s ; we have:

$1 \ rev/s = 2 \pi \ \ rad/s$

$\omega_2 = 4.3 * 2 \pi \ \ rad/s$

$\omega_2 = 27.02 \ \ rad/s$

Therefore the resulting angular speed after she pulls her hand inwards in (rad/s) = 27.02 rad/s

8 0

2 years ago

1. Which of the following is closest to having a mass of 1 kilogram?

Bingel [31]

Answer:

C. One liter of water

Explanation:

One liter of water is closest to 1 kilogram. The other options don't make sense because a dime cannot be close to a mass of 1 kilogram, neither an average size banana or an average person

PLEASE DO MARK ME AS BRAINLIEST IF MY ANSWER IS HELPFUL ;) 

8 0

2 years ago

Somebody please help me my grade depends on it

Darya [45]

Answer: Hope this helps!

Explanation:

a rock formed from particles that are deposited and lithified are sedimentary.

rocks formed from cooling and hardening magma or lava is igneous.

a rock formed when an already existing rock is subjected to extreme heat and pressure is metamorphic.

8 0

2 years ago